What is wrong with the following statement: When you exert a force on a baseball, the equal and opposite force on the ball balan
1 answer:
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Speed with which initially car is moving is 21 m/s
Reaction time = 0.50 s
distance traveled in the reaction time d = v t
d = 21 * 0.50 = 10.5 m
deceleration after this time = -10 m/s^2
now the distance traveled by the car after applying bakes
so total distance moved before it stop
d = 22.05 + 10.5 = 32.55 m
so the distance from deer is 35 - 32.55 = 2.45 m
now to find the maximum speed with we can move we will assume that we will just touch the deer when we stop
so our distance after brakes are applied is d = 35 - 10.5 = 24.5 m
again by kinematics
so maximum speed would be 22.1 m/s
Answer:
1.00 m/s^2
Explanation:
The problem can be solved by using Newton's second law:
where
F is the net force acting on an object
m is the mass of the object
a is its acceleration
In this problem, F=35 N (the force applied by Amber) and
is the mass of the wagon + the brother, so the acceleration of the wagon and the brother is
Answer:
a)10.28 Nm
b)9.93 Nm
Explanation:
Let g = 9.81m/s2. First we can calculate the weight of the trophy
W = mg = 1.6 * 9.81 = 15.696 N
(a) The torque is product of force and its moment arm
T = WL = 15.696 * 0.655 = 10.28 Nm
(b) Suppose his arm makes an angle of 15 degree with respect to the horizontal line. We can still calculate the arm length, or the horizontal distance from the trophy to the champion:
Again, torque is product of force and its moment arm