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FinnZ [79.3K]
3 years ago
7

Three light bulbs are wired in series. What happens if one of these light bulbs burn out

Physics
2 answers:
zysi [14]3 years ago
8 0

Answer:

Explanation:

Use the diagram and the drop-down menu to answer the question.

If bulb C burns out, what will happen to bulbs A and B? ____They will both go out.

thats the answer for edgenuit

devlian [24]3 years ago
7 0
The resistance would go down since you essentially have one less resistor 
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The drawing shows two frictionless inclines that begin at ground level (h = 0 m) and slope upward at the same angle θ. One track
Elena L [17]

Answer:

a). H=2.45m

b). H_{max}=1.94m

Explanation:

For the block that stays on the track, its maximal height is attained when all of the kinetic energy  is converted to potential energy

a).

The height for the block on the longer track can by find using this equation:

\frac{1}{2}*m*v_o^2=m*g*H

Cancel the mass as a factor in each element in the equation

H=\frac{v_o^2}{2*g}

H=\frac{(6.94m/s)^2}{2*9.8m/s^2}

H=2.45m

b).

The other lost some kinetic energy so, use a projectile motion to determine the total height for the other bock:

E_k=E_p

E_k=m*g*H_1

E_k=\frac{1}{2}*m*v_o^2-\frac{1}{2}*m*v^2

m*g*H_1=\frac{1}{2}*m*(v_o^2-v^2)

Solve to v'

v^2=v_o^2-2*g*H_1

v=\sqrt{v_o^2-2*g*H_1}=\sqrt{(6.94m/s)^2-2*9.8m/s^2*1.25m}

v=4.8m/s

H_{max}=H_1+\frac{v^2*sin(50)}{2*g}=1.25m+\frac{(4.8m/s)^2*sin(50)}{2*9.8m/s^2}

H_{max}=1.94m

8 0
3 years ago
Read 2 more answers
When the amplitudes of waves are equal, which frequency waves have the most energy?​
Molodets [167]

Answer:

higher frequency waves will have more energy

Explanation:

5 0
1 year ago
What is the mechanical advantage of a single pulley
Viktor [21]

the answer is 1 because a single pulley has 1 rope


5 0
3 years ago
Read 2 more answers
Show that the optimal launch angle for a projectile subject to gravity is 45o by carrying out the following steps: 6. Write down
Lorico [155]

Answer:

sin  2θ = 1    θ=45

Explanation:

They ask us to prove that the optimal launch angle is 45º, for this by reviewing the parabolic launch equations we have the scope equation

            R = Vo² sin 2θ / g

Where R is the horizontal range, Vo is the initial velocity, g the acceleration of gravity and θ the launch angle. From this equation we see that the sine function is maximum 2θ = 90 since sin 90 = 1 which implies that θ = 45º; This proves that this is the optimum angle to have the maximum range.

We calculate the distance traveled for different angle

          R = vo² Sin (2 15) /9.8

          R = Vo² 0.051 m

In the table are all values ​​in two ways

Angle (θ)                  distance R (x)

 0                 0                     0

15                 0.051 Vo²        0.5 Vo²/g

30                0.088 vo²        0.866   Vo²/g

45                0.102 Vo²        1   Vo²/g

60                0.088 Vo²      0.866   Vo²/g

75                0.051 vo²        0.5   Vo²/g

90                0                     0

See graphic ( R Vs θ)  in the attached ¡, it can be done with any program, for example EXCEL

6 0
2 years ago
You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has—— energy. Calculate
Slav-nsk [51]

Answer:

945 j

Explanation:

You have just given the ball kinetic energy, which is given by the following equation:

KE= 1⁄2 m v2 = 1⁄2 (2.1 kg)(30 m/s)2 = 945 Joules

3 0
3 years ago
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