Answer:

Explanation:
Given:
width of the wire, 
thickness of the flat wire, 
length of the wire, 
voltage across the wire, 
current through the wire, 
Now the net resistance of the wire:
using ohm's law



We have the relation between the resistivity and the resistance as:

where:
a = cross sectional area of the wire
resistivity of the wire material


(a) The maximum potential difference across the resistor is 339.41 V.
(b) The maximum current through the resistor is 0.23 A.
(c) The rms current through the resistor is 0.16 A.
(d) The average power dissipated by the resistor is 38.4 W.
<h3>Maximum potential difference</h3>
Vrms = 0.7071V₀
where;
V₀ = Vrms/0.7071
V₀ = 240/0.7071
V₀ = 339.41 V
<h3> rms current through the resistor </h3>
I(rms) = V(rms)/R
I(rms) = (240)/(1,540)
I(rms) = 0.16 A
<h3>maximum current through the resistor </h3>
I₀ = I(rms)/0.7071
I₀ = (0.16)/0.7071
I₀ = 0.23 A
<h3> Average power dissipated by the resistor</h3>
P = I(rms) x V(rms)
P = 0.16 x 240
P = 38.4 W
Learn more about maximum current here: brainly.com/question/14562756
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