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german
3 years ago
9

Multiplication in exponential notation

Mathematics
2 answers:
Jobisdone [24]3 years ago
6 0

Multiplication and Division. Quantities with exponents can be multiplied and divided easily if they have the same base. Since all number in scientific notation have base 10, we can always multiply them and divide them. To multiply two numbers in scientific notation, multiply their coefficients and add their exponents.

ivolga24 [154]3 years ago
6 0

Okay, examples of Multiplication in exponential notation:

2 * 2 * 2 = 2³

3 * 3 = 3²

The way it works is that you look at how many factors of a number there are (How many times you see the same number multiplied by its self in a row) and take that number and put it in smaller form, to the top right of the original number. That is called an exponent.

There were three twos multiplied by each other, so I put an exponent of 3 next to a two, the exponent means that the 2 is multiplied by its self 3 times. Same with the 3 to the 2ed power. There were two threes, and so I put a 2 as the exponent of 3.

So 2³ = 2 * 2 * 2 = 8.

We get 8 because 2 * 2 is 4, then multiply 4 by 2, we get 8. Once you break it down, exponents can become really simple! Just keep practicing! I hope that this helped!

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For this word problem, it seems confusing with the wording but the equation would just be:

968÷10=x

solving for x, we get 484/5.

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Step-by-step explanation:

If you don't replace the first red marble, it decreases the number of red marbles in the mix, making the proportion of blue marbles relatively larger. For example, if there were 5 red and 5 blue marbles, there would be a 50% chance of drawing a blue marble. If the red drawn is not replaced, there is a 5/9 chance of drawing a blue marble, or a 55% chance of drawing one.

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Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa
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a. <u>0.5 or 50%</u>

b. <u>0.496 or 49.6%</u>

c. <u>0.8185 or 81.85%</u>

d. <u>Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm</u>

e. <u>0.0252 or 2.52%</u>

f. <u>The qualifying speed would be 47.4 wpm.</u>

Step-by-step explanation:

a. Let's find the z-score this way:

μ  = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

<u>p (z=0) = 0.5 or 50%</u>

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

<u>p (z = -0.01) = 0.496 or 49.6%</u>

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

c.

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

<u>In consequence,</u>

<u>p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%</u>

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

<u>Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.</u>

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

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Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

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p = 0.1587 * 0.1587

<u>p = 0.0252 or 2.52%</u>

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z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

<u>The qualifying speed would be 47.4 wpm.</u>

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