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lubasha [3.4K]
3 years ago
8

Which equation can you use to solve for the volume of the cake?

Mathematics
1 answer:
lesantik [10]3 years ago
7 0

Answer:

C. (40 × 60 × 10) + (30 × 60 × 10) = V

Step-by-step explanation:

Picture of the cake can be found in the attachment below :

To solve, we resolve the cake into two distinct boxes :

The lower which is lateral sits parallel, whose volume, = (length * width * height) = (60 * 30 * 10)

And the other which sits vertically ;

Volume = (length * width * height) = (10 * 60 * 40)

Then, we add;

Overall volume:

(60 * 30 * 10) + (10 * 60 * 40)

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Equivalent expression of 8x+12-x
natka813 [3]

Answer:

7x+12 because there is 8x then you subtract 1x which 'll equal 7x and add the 12

7 0
3 years ago
Correct answer only plz thank you!
strojnjashka [21]

Answer:

B

Step-by-step explanation:

GI is made up of the segments GH and HI. In other words:

GI=GH+HI

We know that GH is 2 and GI is 7. Substitute:

7=2+HI

Subtract 2 from both sides:

HI=5

So, our answer is B.

And we're done!

3 0
3 years ago
oakwood has a mass of 2.85 kilograms and a volume of 4100 cubic centimeters. determine the density of oak in grams per cubic cen
bogdanovich [222]

Answer:

The density of oak is <u>0.695</u> grams per cubic centimeter.

Step-by-step explanation:

Given:

Oakwood has a mass of 2.85 kilograms and a volume of 4100 cubic centimeters.

Now, to find the density of oak in grams per cubic centimeter.

Mass (m) = 2.85 kilograms.

So, using conversion factor we convert into grams:

2.85\times 1000=2850\ grams.

Volume (v) = 4100 cubic centimeters.

Now, to get the density by using formula:

Density=\frac{mass}{volume} \\Density=\frac{m}{v}

Density=\frac{2850}{4100}

Density=0.695\ grams\ per\ cubic\ centimeter.

Therefore, the density of oak is 0.695 in grams per cubic centimeter.

6 0
3 years ago
What is the slope of the line
olya-2409 [2.1K]

Answer:

-1

Step-by-step explanation:

The rise over run is -2 over -2.

-2/-2=-1

3 0
3 years ago
A delivery truck is transporting boxes of two size: the combined weight of a large box and a small box is 65 pounds. The truck i
Bas_tet [7]

pretty much about the same as before.

a = weight of a large box

b = weight of a small box.

we know their combined weight is 65 lbs, thus a + b = 65.

we also know that the truck has 60 large ones, and 55 small ones, thus 60*a is the total weight for the large ones and 55*b is the total weight for the small ones, and we know that is a total of 3775, 60a + 55b = 3775.

\bf \begin{cases} a+b=65\\ \boxed{b}=65-a\\ \cline{1-1} 60a+55b=3775 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{60a+55\left( \boxed{65-a} \right)=3775} \\\\\\ 60a+3575-55a=3775\implies 5a+3575=3775\implies 5a=200 \\\\\\ a=\cfrac{200}{5}\implies \blacktriangleright a = 40 \blacktriangleleft \\\\\\ \stackrel{\textit{since we know that}}{b=65-a\implies }b=65-40\implies \blacktriangleright b=25\blacktriangleleft

6 0
4 years ago
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