Answer:
he /she must be patient as a teacher
ANSWER

EXPLANATION
The first equation is

The second equation is

We want to eliminate y, so we multiply the first equation by



We now subtract equation (3) from (2)



Multiply both sides by



Substitute into the first equation to solve for x .

Multiply to obtain



Multiply both sides by 2.


The solution is

D. 989 sq.m should be the right answer
5p - 3q = -39
- (-2p - 3q = 3)
==> 7p = -42 ==> p = -6
==> p = -6
-2(-6) - 3q = 3 ==> 12 - 3q = 3
==>p = -6
-3q = 3 - 12 ==> -3q = -9
==> p = -6
q = 3
Answer:
-7(9) < -56
Step-by-step explanation:
-7(9) is -63 which is less than -56 so anything above that is less than 56-