Answer:
The volume of the empty space is
Step-by-step explanation:
we know that
The volume of the empty space inside the box is equal to the volume of the box minus the volume of the soccer ball
step 1
Find the volume of the box
The length side of the cube is equal to the diameter of the soccer ball
Let
b -----> the length side of the box
we have
The volume of the box is equal to the volume of a cube
substitute
step 2
Find the volume of the soccer ball
The volume of the sphere (soccer ball) is equal to
we have
substitute
step 3
Find the volume of the empty space
Answer:
see explanation
Step-by-step explanation:
Divide through by 2
2a² - 5a + 3 = 0
To factor the quadratic
Consider the factors of the product of the coefficient of the a² term and the constant term which sum to give the coefficient of the x- term
product = 2 × 3 = 6 and sum = - 5
The factors are - 2 and - 3
Use the factors to split the a- term
2a² - 2a - 3a + 3 = 0 ( factor the first/second and third/fourth terms )
2a(a - 1) - 3(a - 1) = 0 ← factor out (a - 1)
(a - 1)(2a - 3) = 0
Equate each factor to zero and solve for a
a - 1 = 0 ⇒ a = 1
2a - 3 = 0 ⇒ 2a = 3 ⇒ a =
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So the "back" of the arrow is on/above -20.
The arrow points to -12.
You added something to -20 to get to -12.
So the first number is -20. You added ? to get -12. -12 is the last number / the answer to the equation.
So the equation from what you have so far is -20 + ? = -12
You need to isolate the ? so that you know what it is.
So to get rid of the -20 (make it 0), you have to add 20. -20 plus 20 equals 0, which basically means it is gone. You also have to add 20 to -12. 20 plus -12 equals 8.
Now the equation is ? = 8.
So you know that the second number is 8.
The equation makes sense; -20 + 8 = -12.
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Answer:
Part 1
Type II error
Part 2
No ; is not ; true
Step-by-step explanation:
Data provided in the question
Mean = 100
The Random sample is taken = 43 students
Based on the given information, the conclusion is as follows
Part 1
Since it is mentioned that the classes are successful which is same treated as a null rejection and at the same time it also accepts the alternate hypothesis
Based on this, it is a failure to deny or reject the false null that represents type II error
Part 2
And if the classes are not successful so we can make successful by making type I error and at the same time type II error is not possible
Therefore no type II error is not possible and when the null hypothesis is true the classes are not successful