Answer:
1.
centre(h,k)=(-13,9)
radius (r)=6
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x+13)²+(y-9)²=6²
x²+26x+169+y²-18y+81=36
x²+y²+26x-18y+169+81-36=0
x²+y²+26x-18y +214=0
is a required equation of the circle.
2.
centre(h,k)=(1,-1)
radius (r)=11
we have
equation of the circle is
(x-h)²+(y-k)²=r²
(x-1)²+(y+1)²=11²
x²-2x+1+y²+2y+1=121
x²+y²-2x+2y=121-2
x²+y²-2x+2y=119
is a required equation of the circle.
Answer:
slope=6/5
Step-by-step explanation:
The formula for finding the slope is y1-y2/x1-x2=slope. So if we substitute in the numbers from you question, it would be (-3-3)/(-2-3)=slope
(-3-3)/(-2-3)=slope
-6/-5=slope
6/5=slope
Answer:
Step-by-step explanation:
the upper left graph is the correct answer
because "... or equal to" always represents a filled dot, while just "greater/less than" represents blank dot
Answer:
C. angle bisector
Step-by-step explanation:
The line segments between (4,-6) and (-6,-16) is 1.
slope = y2 -y1 /x2-x1 = -16+6/-6-4=-10/-10=1
