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aleksley [76]
2 years ago
10

A. 3/13 B. 10/39 C. 5/12 D. 8/13

Mathematics
1 answer:
ELEN [110]2 years ago
4 0
The equation to find P(A and B) is P(A and B)= P(A) x P(B/A). P(B/A) stands for probability of B given A. First we need to find out the P(A). The P(A) is 8/13 because you have 13 marbles total and 8 white marbles. For P(B/A), it is 5/12. This is because there are 5 red marbles and given that A happened, there would only be 12 marbles left in the bag, leaving you with a 5/12 chance of getting a red marble. Now plug it in. 8/13 x 5/12 = 40/156, which simplifies down to 10/39. Thus, B is the answer.
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kobusy [5.1K]

Answer: 76

Step-by-step explanation:

If a pair of parallel lines are cut by a line, the alternate angles are equal to each other. The angles 76 and x are alternate angles, so that means they are equal.

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Which of the following is the sum of the slopes of the line 3x+y=1 and a line perpendicular to this line? A 0 B 13 C −83 D −6
laiz [17]

Answer:

-8/3

Step-by-step explanation:

First find the slope of the line

3x+y = 1

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y = -3x+1

This is in slope intercept form

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3 0
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What is (f-g)(x)?<br><br> f(x)=x^4-x^2+9<br> g(x)=x^3+3x^2+12
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7 0
2 years ago
I need to send photos.
frez [133]

SOLUTION:

Step 1:

From the given question, and comparing the scores in classes A and B

Step 2:

Question one, to know the class which had the better overall result on the exam;

(I) The scores in class A ranges from 65 to 100, while that of class B ranges from 60 to 90. This explains that class A had better results.

(ii) The median of the scores in class A is 85, while the median of the scores in class B is 75, this is another piece of supporting evidence that class A had better results.

Step 3:

Question two, to know the class which had greater variability in the results;

For a better understanding of this question, I need to explain the concept of variability in statistics.

Variability in statistics refers to the difference being exhibited by data points within a data set, as related to each other or as related to the mean. This can be expressed through the range, variance or standard deviation of a data set.

Step 4:

So we need to find the range of scores in each of the two classes and then compare, the class with the greater range has the greater variability.

The Range is the difference between the lowest and highest score (H - L), where H is the highest score and L is the lowest score.

Step 5:

Applying the formula for range stated in step 4;

For Class A; H = 100 and L = 65

For Class B; H = 90 and L = 60

The range for class A; H - L = 100 - 65 = 35

The range for class B; H - L = 90 - 60 = 30

By comparing the range of class A and that of B, it is clear that Class A had a greater range (variability)

CONCLUSION:

Class A had better overall results in the exam and greater variability in the results.

6 0
9 months ago
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