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Norma-Jean [14]
3 years ago
7

Write a compound inequality to represent all of the numbers between -4 and 6.

Mathematics
1 answer:
11111nata11111 [884]3 years ago
8 0

Answer:

-4 ≤ x ≤ 6

Step-by-step explanation:

Firstly, let us have a random number between the two digits

We can call this random number x

So now, we have to position x between these two numbers

So to ensure that the two numbers are in the range of our values, we have to use an equality statement that will cover both

So by using lesser than or equal to we can incorporate the two extremes

The inequality here is thus ;

-4 ≤ x ≤ 6

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A=12h(a+b)
EastWind [94]

<span>A=12h(a+b) 
Solve for h.

</span>All these answers are incorrect
<span>A. h=2Aa+b
B.h=a+b2A
C.h=A2(a+b)
D.h=2(a+b)A

The answer is 
h = A / 12(a+b)
h = \frac{A}{12(a+b)}</span>
6 0
2 years ago
What is the complete factorization of 8x2 − 8x + 2?
Luden [163]

Answer:

Step-by-step explanation:

8x^2 - 8x + 2

2(4x^2 - 4x + 1)

2(2x - 1)(2x - 1) or 2(2x - 1)^2

answer is C

7 0
2 years ago
Read 2 more answers
Write the coefficient of x in
iren [92.7K]

Answer:a

Step-by-step explanation:

8 0
2 years ago
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The midpoint of AB is M(-2, 5). If the coordinates of A are (1, 7), what are the coordinates of B?
irinina [24]

Answer:

(-5, 3)

Step-by-step explanation:

The midpoint formula: (\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2})

Now, if we work backwards, starting with the x-coordinate

-2 * 2 = -4 - 1 = -5

Then, the y-coordinate

5 * 2 = 10 - 7 = 3

We reach our answer of (-5, 3). A good habit would be to plug these points back into the formula to check if your answer is correct.

7 0
2 years ago
En un supermercado tienen dos contadores eléctricos de flujo de personas 1 registra de 3 en 3 y el otro de 5 en 5 en el momento
Licemer1 [7]

Answer:

El contador que señala 840 registra de 3 en 3.

Step-by-step explanation:

Existe un truco para determinar si un número es múltiplo de 3, si la suma de sus dígitos es 3 o uno de sus múltiplos, entonces el número es un múltiplo de 3. En consecuencia, corresponde al contador eléctrico que registra de 3 en 3 y el otro contador eléctrico sería el que registra de 5 en 5.

Primer contador: 840

x = 8+4+0

x = 12

12 es un múltiplo de 3, por tanto, este contador es el que registra de 3 en 3.

Segundo contador: 560

x = 5+6+0

x = 11

11 no es un múltiplo de 3. Asimismo, todo número que sea múltiplo de 5 termina en 5 o 0, entonces este contador es el que registra de 5 en 5.

El contador que señala 840 registra de 3 en 3.

3 0
3 years ago
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