15^2 + 20^2
= 225 + 400
= 625
square root of 625 = 25
answer:<span>length of the Hypotenuse is</span> 25
When the squared terms are of different signs, the equation generally describes a hyperbola. This one has its vertices at x=±30, so the parameters of interest are
domain: (-∞, -30] ∪ [30, ∞)
range: (-∞, ∞)
identity used is
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
then use
(x+y+z)² = x²+y²+z²+2(xy+yz+xz)
225= 83 + 2(xy+yz+xz)
xy+yz+xz = (225-83)/2
xy+yz+xz= 142/2
xy+yz+xz= 71
ok
now use identity
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
now
x³ + y³+ z³– 3xyz = 15 (83 – xy – yz – zx).
= 15[83 - (71)]
= 15×12
=180
P^2 - 9
p^2 - 3^2
(p+3)(p-3)
Hope this helps!
I think its 1/6 because if yoh do 1/3 times 1/2 it equals 1/6???????? not sure
