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Artemon [7]
4 years ago
14

Binding of a signaling molecule to which type of receptor leads directly to a change in the distribution of ions on opposite sid

es of the membrane?
Physics
1 answer:
aalyn [17]4 years ago
5 0

Binding of a signaling molecule to ligand-gated ion channel leads directly to a change in the distribution of ions on opposite sides of the membrane

<u>Explanation:</u>

The ligand-gated-ion-channel is trans membrane protein buildings that conduction course through the channel pores in light of the official of a neurotransmitter. They are not quite the same as voltage - gated - ion - channels, which are delicate to film possibilities, and G-protein coupled receptors (GPCR's), which utilize second messengers.

These ion channels, additionally ordinarily referred to as ionotropic receptors, are a gathering of trans membrane -ion-channel proteins which open to permit ions, for example, N a^{+}, K^{+} and potentially c l^{-} to go through the layer in light of the official of a synthetic errand person, for example, a neurotransmitter.

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A radio signal has a frequency of 1.023 x 108 HZ. If the speed of the signal in air is 2.997 x 108m/s, what is the wavelength of
Sladkaya [172]

Answer:

2.93 m  (which agrees with answer "C" on the list)

Explanation:

Recall that the speed of the wave equals the product of the wave's length times its frequency. Therefore, the wavelength is going to be the quotient of the speed of the signal divided its frequency:

Wavelength = 2.997  10^8 / 1.023  10^8 =  2.93 m

5 0
3 years ago
Why is speed a scaler quantity​
In-s [12.5K]

Answer:

Speed is a scalar quantity it is the rate of change in the distance travelled by an object, while velocity is a vector quantity  it is the speed of an object in a particular direction.

4 0
4 years ago
Sherlock Holmes examines a clue by holding his magnifying glass (with
Alborosie

Answer:

Distance: -30.0 cm; image is virtual, upright, enlarged

Explanation:

We can find the distance of the image using the lens equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where:

f = 15.0 cm is the focal length of the lens (positive for a converging lens)

p = 10.0 cm is the distance of the object from the lens

q is the distance of the image from the lens

Solving for q,

\frac{1}{q}=\frac{1}{f}-\frac{1}{q}=\frac{1}{15.0}-\frac{1}{10.0}=-0.033\\q=\frac{1}{0.033}=-30.0 cm

The negative sign tells us that the image is virtual (on the same side of the object, and it cannot be projected on a screen).

The magnification can be found as

M=-\frac{q}{p}=-\frac{-30}{10}=3

The magnification gives us the ratio of the size of the image to that of the object: since here |M| = 3, this means that the image is 3 times larger than the object.

Also, the fact that the magnification is positive tells us that the image is upright.

8 0
4 years ago
How do you calculate gravity’s pull?
WINSTONCH [101]

Answer:

The gravitational force between a mass and the Earth is the object's weight. Mass is considered a measure of an object's inertia, and its weight is the force exerted on the object in a gravitational field. On the surface of the Earth, the two forces are related by the acceleration due to gravity: Fg = mg.

4 0
3 years ago
Read 2 more answers
Which shows the correct lens equation?
zhuklara [117]

Answer:

The inverse of f equals the inverse of d Subscript o Baseline plus the inverse of d Subscript I Baseline.

Explanation:

Explanation:

5 0
3 years ago
Read 2 more answers
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