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4 years ago

Do solid particles vibrate?

1 answer:

3 0

The answer to this question about solid particles would be B. Yes, they vibrate about a fixed point.

It is important to remember that the basic difference of the 3 states of matter is how their molecules are arranged. Gas molecules are situated far from each other which gives the molecules space to freely move around giving the gas its characteristics. Liquid molecules, on the other hand, are situated near to each other, where there is still space that let's them move but not as free as gas molecules. Solid molecules are very close to each other that the phrase tightly packed is but an understatement. This is also a reason that when solid particles vibrate, usually when heated, it is only about a fixed point.

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Write down the equation that links energy transferred, charge flow, and potential difference.

laiz [17]

Answer:

The description of the given scenario is described in the explanation segment below.

Explanation:

As a charge passes through some kind of potential gap, the electrical task is undertaken as well as energy will be transferred.
The Potential difference seems to be an amount of work performed per unit charge and is denoted by "V" as well as a charge is denoted by "Q".

The energy transferred could be determined by using the following equation or formula:

⇒ Energy transferred = charge × potential difference

6 0

3 years ago

A 2,100 kg car is lifted by a pulley. If the cable breaks at 4.50 m, what is the velocity of the car when it hits the ground? 88

sammy [17]

V^2-u^2=2as

v=final velocity=unkown
u=initial velocity=0 m/s, because freely falling
a=acceleration due to gravity=9.8 m/s^2
s=distance (here height) traveled=4.5m

therefore the final velocity,
v^2=2*9.8*4.5
v=9.39m/s

8 0

3 years ago

Can someone help me with these two please.

Alex17521 [72]

Could you scroll up a little so I can see the first part of the question- I MIGHT be able to help you then. Thanks!

3 0

3 years ago

Read 2 more answers

A vertical straight wire carrying an upward 28-A current exerts an attractive force per unit length of 7.83 X 10 N/m on a second

JulijaS [17]

Answer:

$i_2 = 978750 A$

Since the force between wires is attraction type of force so current must be flowing in upward direction

Explanation:

Force per unit length between two current carrying wires is given by the formula

$F = \frac{\mu_0 i_1 i_2}{2 \pi d}$

here we know that

$F = 7.83 \times 10 N/m$

$d = 7.0 cm = 0.07 m$

$i_1 = 28 A$

now we will have

$F = \frac{4\pi \times 10^{-7} (28.0)(i_2)}{2\pi (0.07)}$

$7.83 \times 10 = \frac{2\times 10^{-7} (28 A)(i_2)}{0.07}$

$i_2 = 978750 A$

Since the force between wires is attraction type of force so current must be flowing in upward direction

3 0

3 years ago

If a 0.15 kg ball falls and has a KE of 20 J just before striking the ground, from what height did it fall. A. 1.36m B. 3m C. 13

RUDIKE [14]

According to the conservation of mechanical energy, the kinetic energy just before the ball strikes the ground is equal to the potential energy just before it fell.

Therefore, we can say KE = PE
We know that PE = m·g·h

Which means KE = m·g·h

We can solve for h:

h = KE / m·g
= 20 / (0.15 · 9.8)
= 13.6m

The correct answer is: the ball has fallen from a height of 13.6m.

5 0

3 years ago