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AlexFokin [52]
3 years ago
7

2. In each of A, B, C, & D below, a sphere is moving from left to right next 20 points

Physics
1 answer:
laila [671]3 years ago
8 0

Answer:

zero

rank the magnitude of the average velocity over the first 2 second

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The way roughness of surfaces affects kinetic friction is called the __________ of kinetic friction?
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Answer:

coefficient

Explanation:

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As a tractor pulls a plow across a field, it exerts a force on the plow in the forward direction. What is the "equal and opposit
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the force of the plow pulling backward on the tractor

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3 years ago
An automobile battery has an emf of 12.6 V and an internal resistance of 0.0600 . The headlights together present equivalent res
murzikaleks [220]

Answer:

(a) V=11.86\ V

(b) V=9.76\ V

Explanation:

<u>Electric Circuits</u>

Suppose we have a resistive-only electric circuit. The relation between the current I and the voltage V in a resistance R is given by the Ohm's law:

V=R.I

(a) The electromagnetic force of the battery is \varepsilon =12.6\ V and its internal resistance is R_i=0.06\ \Omega. Knowing the equivalent resistance of the headlights is R_e=5.2\ \Omega, we can compute the current of the circuit by using the Kirchhoffs Voltage Law or KVL:

\varepsilon=i.R_i+i.R_e=i.(R_i+R_e)

Solving for i

\displaystyle i=\frac{\varepsilon}{ R_i+R_e}=\frac{12}{0.06+5.2}=2.28\ A

i=2.28\ A

The potential difference across the headlight  bulbs is

V=\varepsilon  -i.R_i=12\ V-2.28\ A\cdot 0.06\ \Omega=11.86\ V

V=11.86\ V

(b) If the starter motor is operated, taking an additional 35 Amp from the battery, then the total load current is 2.28 A + 35 A = 37.28 A. Thus the output voltage of the battery, that is the voltage that the bulbs have is

V=\varepsilon  -i.R_i=12\ V-37.28\ A\cdot 0.06\ \Omega=9.76\ V

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3 years ago
Which one of the following statements is true concerning the magnitude of the electric field at a point in space? It is a measur
IceJOKER [234]

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It is a measure of the electric force per unit charge on a test charge.

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The magnitude of the electric field is defined as the force per charge on the test charge.

Since we define electric field as the force per charge, it will have the units of  force divided by the unit of charge. This implies that the SI unit of electric field is given as Newton/Coulomb (N/C).

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When air cools, it holds _____ water than when it is warmer.
Blizzard [7]
It holds A. Less water than when it is warmer.
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3 years ago
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