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3 years ago

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How many integer solutions are there to the equation x^3-5x^2+2x+13=5

2 answers:

LuckyWell [14K]3 years ago

7 0

Hello,

To find the solutions to this, you can either graph it on a graphing calculator or factor it.

If you factor it, first set it equal to 0 by subtracting 5 from both this.
The you can factor it to: (x - 2)(x - 4)(x + 1) = 0
Using the zero product rule, our solutions are 2, 4, and -1.

There are 3 integer solutions.

Good luck,
MrEQ

vagabundo [1.1K]3 years ago

6 0

Three possible solutions

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Step-by-step explanation:

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and the minus...

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