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4 years ago

Can 4/3 be simplified ?

Mathematics

2 answers:

11Alexandr11 [23.1K]4 years ago

7 0

Answer:

Step-by-step explanation:

no, because 4 goes n to 2 but 3 doesn't go in to anthing.

Novosadov [1.4K]4 years ago

6 0

Answer: yes, 4/3 can be simplified

Step-by-step explanation:

Since it is an improper fraction, it can be simplified.

three goes into four once, And there is a remainder of one. so the new fraction is: 1 1/3

You might be interested in

Subtract the fractions and simplify the answer 13/15 -2 2/3

Solnce55 [7]

2 2/3 = 8/3

8/3= 40/15

13/15 - 40/15 = -27/15 = -1 12/15

8 0

4 years ago

Find the equation perpendicular to the line y=−3x+5 that passes through point (2, 6).

ololo11 [35]

Hey there! :)

Perpendicular to y = -3x + 5 ; passes through (2, 6).

Our slope is -3. We know this because it is in the "m" position from slope-intercept form. However, since our equation we're looking for is perpendicular to our given one, we must find the negative reciprocal of -3.

A negative reciprocal is simply a number that is flipped and either given a negative or gets a negative removed.

So the negative reciprocal of -3 is 1/3. This means that our new slope is 1/3.

Now, using point-slope form ( y-y₁=m(x-x₁) ), our new slope (1/3) & (2, 6) , let's find our new equation!

y-y₁=m(x-x₁) y - (6) = 1/3(x - 2)

Simplify.

y - 6 = 1/3x - 2/3

~Hope I helped!~

5 0

4 years ago

Read 2 more answers

Find all the solutions in there interval (0,2pi) for cos5x=-1/2

oee [108]

Answer:

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

Step-by-step explanation:

Solving trigonometric equations.

We are given a condition and we must find all angles who meet it in the provided interval. Our equation is

$cos5x=-\frac{1}{2}$

Solving for 5x:

$5x=\frac{2\pi}{3}+2n\pi$

$5x=\frac{4\pi}{3}+2n\pi$

The values for x will be

$x=\frac{\frac{2\pi}{3}+2n\pi}{5}$

$x=\frac{\frac{4\pi}{3}+2n\pi}{5}$

To find all the solutions, we'll give n values of 0, 1, 2,... until x stops belonging to the interval $(0,2\pi)$

For n=0

$x=\frac{\frac{2\pi}{3}}{5}=\frac{2\pi}{15}$

$x=\frac{\frac{4\pi}{3}}{5}=\frac{4\pi}{15}$

For n=1

$x=\frac{\frac{2\pi}{3}+2\pi}{5}=\frac{8\pi}{15}$

$x=\frac{\frac{4\pi}{3}+2\pi}{5}=\frac{2\pi}{3}$

For n=2

$x=\frac{\frac{2\pi}{3}+4\pi}{5}=\frac{14\pi}{15}$

$x=\frac{\frac{4\pi}{3}+4\pi}{5}=\frac{16\pi}{15}$

For n=3

$x=\frac{\frac{2\pi}{3}+6\pi}{5}=\frac{4\pi}{3}$

$x=\frac{\frac{4\pi}{3}+6\pi}{5}=\frac{22\pi}{15}$

For n=4

$x=\frac{\frac{2\pi}{3}+8\pi}{5}=\frac{26\pi}{15}$

$x=\frac{\frac{4\pi}{3}+8\pi}{5}=\frac{28\pi}{15}$

For n=5 we would find values such as

$x=\frac{\frac{2\pi}{3}+10\pi}{5}=\frac{32\pi}{15}$

$x=\frac{\frac{4\pi}{3}+10\pi}{5}=\frac{34\pi}{15}$

which don't lie in the interval $(0,2\pi)$

The whole set of results is

$\frac{2\pi}{15},\frac{4\pi}{15},\frac{8\pi}{15},\frac{2\pi}{3},\frac{14\pi}{15}, \frac{16\pi}{15}, \frac{4\pi}{3},\frac{22\pi}{15}, \frac{26\pi}{15}, \frac{28\pi}{15}$

6 0

4 years ago

HELP WILL GIVE BRAINLIEST!!

Vikentia [17]

Answer:

160 in^2

Step-by-step explanation:

5 0

3 years ago

Jim needs to buy office supplies for a company. Pens are $0.15 each and he would like to buy 3 pens for each employee plus an ex

vekshin1

He will spend $75.15 on the pens.

8 0

4 years ago