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3 years ago

Can 4/3 be simplified ?

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

no, because 4 goes n to 2 but 3 doesn't go in to anthing.

Novosadov [1.4K]3 years ago

6 0

Answer: yes, 4/3 can be simplified

Step-by-step explanation:

Since it is an improper fraction, it can be simplified.

three goes into four once, And there is a remainder of one. so the new fraction is: 1 1/3

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A store sells 7 different types of envelopes and 6 different types of postage stamps. How many different combinations are there

solong [7]

Answer

42

Explanation

Let’s say:

Set of envelopes: {a,b,c,d,e,f,g}

Set of postage stamps: {1,2,3,4,5,6}

For an envelope you can have:

1a 2a 3a 4a 5a 6a (6 different combinations)

This applies to all 7 different types of envelopes.

Therefore 7 • 6 = 42

5 0

3 years ago

Pg 8 number 5 and 6 PLZZZ HELP

blsea [12.9K]

Answer:

Part 5) $C=8\pi\ cm$

Part 6) The ratio between the circumference and diameter of a circle, is equal to the number π

Step-by-step explanation:

The questions in the attached figure

Part 5)

we know that

The circumference of a circle is equal to

$C=\pi D$

where

D is the diameter

we have

$D=8\ cm$

substitute

$C=\pi (8)$

$C=8\pi\ cm$

Part 6) What is the ratio between the circumference and diameter of a circle?

we know that

The circumference of a circle is equal to

$C=\pi D$

where

D is the diameter

The ratio between the circumference and diameter of a circle, is equal to divide the circumference by the diameter

$\frac{C}{D}=\frac{\pi D}{D}=\pi$

7 0

3 years ago

In this problem, y = c1ex + c2eâx is a two-parameter family of solutions of the second-order DE y'' â y = 0. Find a solution of

SCORPION-xisa [38]

Answer:

$y(t) = 2e^t -e^{-t}$

Step-by-step explanation:

Assuming this complete problem: "In this problem,

y = c1ex + c2e−x

is a two-parameter family of solutions of the second-order DE

y'' − y = 0.

Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions.

y(0) = 1, y'(0)= 3"

Solution to the problem

For this case we have a homogenous, linear differential equation with order 2, and with the general form:

$ay'' +by' +cy=0$

Where $a =1, b=0, c=-1$

And we can rewrite the differential equation in terms $y = e^{rt}$ like this:

$[e^{rt}]'' -e^{rt}=0$

And applying the second derivate we got:

$r^2 e^{rt} -e^{rt}=0$

We can take common factor $e^{rt}$ and we got:

$e^{rt} (r^2-1) =0$

And for this case the two only possibel solutions are $r=1, r=-1$

And the general solution for this case is given by:

$y = c_1 e^{r_1 t} + c_2 e^{r_2 t}$

Replacing the roots that we found we got:

$y = c_1 e^{t} +c_2 e^{-t}$

Now we can find the derivates for this last espression

$y' = c_1 e^t -c_2 e^{-t}$

$y'' = c_1 e^t +c_2 e^{-t}$

From the initial conditions we have this:

$y(0)=1 =c_1 e^{0} +c_2 e^{-0}= c_1 +c_2$ (1)

$y'(0) =3= c_1 e^{0} -c_2e^{-0}= c_1 -c_2$ (2)

If we add equations (1) and (2) we got:

$4 = 2c_1 , c_1 = 2$

And solving for $c_2$ we got:

$c_2=3-c_1= 3-2 = 1$

So then our general solution is given by:

$y(t) = 2e^t -e^{-t}$

8 0

3 years ago

Helppppp meeeeeeeeeeeeeeeeeee idkkkkk

aev [14]

Answer:

= (3) t + (3) 2

= 3t + 6

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the y-value of p? A. -18 B. -16 C. -12 d. -10

beks73 [17]

B because it’s the right answer I’m telling you it is so believe it

5 0

3 years ago