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3 years ago

8. x < 24 How do you solve the inequality

Mathematics

1 answer:

notsponge [240]3 years ago

6 0

Answer:

x<3

Step-by-step explanation:

8x<24

x<24/8

x<3

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PLEASE HELP ME!!!! I NEED THIS QUICKLY!!

zloy xaker [14]

Part A: $y=-\frac{5}{4} x+\frac{35}{2}$ is the equation of the line.

Part B: Anika worked 17.5 hours on day 0.

Part C: The setup time decreases with 1 hour and 15 min per day.

Explanation:

Part A: Let us find the equation of the line using the points (2,15) and (6,10)

The equation of the line is given by,

$y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \cdot\left(x-x_{1}\right)$

Substituting, we get,

$y-15=\frac{10-15}{6-2} (x-2)$

Simplifying, we have,

$y-15=-\frac{5}{4} (x-2)$

$y-15=-\frac{5}{4} x+\frac{5}{2}$

Subtracting both sides by 15, we get,

$y=-\frac{5}{4} x+\frac{35}{2}$

Hence, the equation of the line is $y=-\frac{5}{4} x+\frac{35}{2}$

Part B: To determine the number of hours Anika worked on day 0, let us substitute x = 0 in the equation of the line.

Thus, we get,

$y=\frac{35}{2}\\y=17.5$

Hence, Anika worked 17.5 hours on day 0.

Part C: The setup time decrease per day can be determined using the slope.

The formula for slope is given by

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substituting , we have,

$m=\frac{10-15}{6-2}=-\frac{5}{4}$

Converting the fraction into hours and minutes, we get,

$-\frac{5}{4}\times60=-75 min$

Since, 1 hour = 60 min

Subtracting 60 and 75 = 15 min

Thus, the setup time decreases with 1 hour and 15 min per day.

6 0

2 years ago

Can you help me with #6???

AnnZ [28]

What are you asking?

6 0

3 years ago

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A card is chosen at random from a standard deck.

allsm [11]

Answer:

6/13

Step-by-step explanation:

There are 52 cards in a deck, and 26 of them are red. There are 2 red queens in a deck, so the probability of choosing a red card that is not a queen is 24/52 = 6/13.

7 0

2 years ago

Read 2 more answers

2y = 2x = 8 y = x + 4

padilas [110]

Answer:

I love algebra anyways

the ans is in the picture with the steps how i got it

(hope that helps can i plz have brainlist it will make my day :D hehe)

Step-by-step explanation:

4 0

3 years ago

What are the real and complex solutions of the polynomial equation? x^3-8=0. with imaginary numbers

seraphim [82]

Answer:

Solutions are 2, -1 + 0.5 sqrt10 i and -1 - 0.5 sqrt10 i

or 2, -1 + 1.58 i and -1 - 1.58i

(where the last 2 are equal to nearest hundredth).

Step-by-step explanation:

The real solution is x = 2:-

x^3 - 8 = 0

x^3 = 8

x = cube root of 8 = 2

Note that a cubic equation must have a total of 3 roots ( real and complex in this case). We can find the 2 complex roots by using the following identity:-

a^3 - b^3 = (a - b)(a^2 + ab + b^2).

Here a = x and b = 2 so we have

(x - 2)(x^2 + 2x + 4) = 0

To find the complex roots we solve x^2 + 2x + 4 = 0:-

Using the quadratic formula x = [-2 +/- sqrt(2^2 - 4*1*4)] / 2

= -1 +/- (sqrt( -10)) / 2

= -1 + 0.5 sqrt10 i and -1 - 0.5 sqrt10 i

4 0

2 years ago

Read 2 more answers