We need to find the number of pies baked in years 1 and 2.
There were 148 pies baked in year 1. 
There were 
pies baked in year 2. 
Rearrange the terms so the variable is first. 
1 and 2 are both rational.
3 and 4 are both not.
First task:
To determine this we need to make difference between system that doesn't have solution and system that has infinite number of solution. If when solving equations we get 0 = 0 that means system has infinite number of equations.
If we get 0 = some number that means that system doesn't have solution.
Multiplying first equation of second system by 2 and adding it to second equation we get 0=0 which means that this system has infinite number of solutions.
Answer is second system
Second task:
For this we need to set a system of equations and solve it. System looks like this:
x + y = 224
x*12 + y*8=2520
-------------------------
x represents older than 18 and "y" 18 and younger than that.
first equation we multiply with -12 and sum it with second.
-4y = -168
y=168/4 = 42
Answer is 42.
Step-by-step explanation:
A(t)=P(e^(rt))
Insert the values as follows:
The equation for "continual" growth (or decay) is A = Pe^(rt), where "A", is the ending amount, "P" is the beginning amount (principal, in the case of money), "r" is the growth or decay rate (expressed as a decimal), and "t" is the time (in whatever unit was used on the growth/decay rate).
34820=P(e^((.78)(5)))
34830=P(49.4024)
704.82335
Hope that helps :)
