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weqwewe [10]
3 years ago
14

Solve: x^2 = 81 x^2 = -9 x^2 = 20 3x^2 = 125

Mathematics
1 answer:
sergeinik [125]3 years ago
3 0
<span>x^2 = 81
x = </span>±√81
x = ±9<span>

x^2 = -9 no solutions 

x^2 = 20
x = </span>±√20
x = <span>±2</span>√5<span>

</span>3x^2 = 125 \\ &#10;x^2 =   \frac{125}{3} \\ x=б \sqrt{ \frac{125}{3} }<span>
</span>
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The length of a rectangle is 8 1/2 inches and the width is 3 1/4 inches. What is the ratio, using whole numbers, of the length t
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Answer:

The general solution of   cos x = cos(\frac{\pi }{6})   is  

                                                x = 2nπ±\frac{\pi }{6}

The general solution values  

                                 x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Step-by-step explanation:

Explanation:-

Given equation is  

                              2cosx-\sqrt{3} =0  for 0

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<em>General solution of cos θ = cos ∝ is θ = 2nπ±∝</em>

<em>Now The general solution of   </em>cos x = cos(\frac{\pi }{6})<em>   is  </em>

<em>                                                 x = 2nπ±</em>\frac{\pi }{6}<em></em>

put n=0

x = - \frac{\pi }{6}  and x = \frac{\pi }{6}

Put n=1  

x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}

x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}

put n=2

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x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}

And so on

But given 0 < x< 2π

The general solution values  

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