The correct answe is D.82
Answer:
Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
Step-by-step explanation:
In order to determine if the poster will lie flat in the box or not, we will determine the length of the sides of the poster and the box, if the length of the side of the square poster is smaller than that of the box, it will lie flat. This is calculated as follows:
Area of poster = 4 square feet
Area of poster = (Length)²
4 = (Length)²
∴ Length = √(4)
Length of poster = 2 Ft
Volume of box = 14 cubic feet
Volume of box = (Length)³
14 = (Length)³
∴ Length = ∛(14)
Length = 2.41 Ft
∴ Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
Answer:
0.675 m/s
Step-by-step explanation:
Let height of shadow= y,CD=x
Height of man=2 m
Speed of man= 

Therefore, 


Differentiate w.r.t t



When the man is 4 m from the building
Then, we have x=12-4=8 m

Substitute the values in above equation then, we get


Substitute the values then we get

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.
Answer:
The multiple zero is
.
The multiplicity is 2
Step-by-step explanation:
The given function is

To find the zero of this function, we equate it to zero.

We factor to obtain;

Observe that; the expression within the parenthesis is a perfect square.
This implies that;

This implies that;
Either
or 
has a multiple zero which is
and its multplicity is 2.