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miskamm [114]
3 years ago
7

I need help Please!​

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
7 0

Answer:

36

Step-by-step explanation:

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Add brackets to the following equation to make it time. 1 + 72 ÷4 × 2 =10
Jet001 [13]

Answer:

1 + 72 ÷4 × 2 =10 with brackets it equals 10

1 + (72 ÷ (4 × 2)) =10

Step-by-step explanation:

6 0
3 years ago
Point Q' is the image of Q (4,-6) is under a translation by 1 unit to the right.
alexandr1967 [171]

Answer:

The coordinates of point Q' would be (5, -6) after being translated 1 unit to the right.

Step-by-step explanation:

4 0
3 years ago
In the diagram, point D is the center of the medium-sized circle that passes through C and E, and it is also the center of the l
mestny [16]

9514 1404 393

Answer:

  5/8

Step-by-step explanation:

The area of the smaller circles is proportional to the square of the ratio of their diameters. The two smallest circles have diameters equal to 1/4 the diameter of the largest circle. Hence their areas are (1/4)^2 = 1/16 of that of the largest circle.

Similarly, the medium circle has a diameter half that of the largest circle, so its area is (1/2)^2 = 1/4 of the are of the largest circle.

The smaller circles subtract 2×1/16 +1/4 = 3/8 of the area of the largest circle. Then the shading is 1-3/8 = 5/8 of the area of the largest circle.

3 0
3 years ago
Rsm geo lol- no idea how to start or do it at all
jek_recluse [69]

Answer:

42, 138, and 138 degrees DON'T FORGET THE DEGREES SIGNS!!!!!

Step-by-step explanation:

Using vertical angles theorem, we can get another 42, 180-42, and 180-42.

So we have 42, 138, and 138

7 0
3 years ago
Please include work
OLga [1]

Answer:

9.     6k + 5 and 2k - 1.

10.    5√2 .

Step-by-step explanation:

9.    Area = 12k^2 + 4k - 5

Factoring:

12k^2 - 6k + 10k - 5

= 6k(2k - 1) + 5(2k - 1)

= (6k + 5)(2k - 1)

So the required lengths are 6k + 5 and 2k - 1.

10.  The ratio of a leg to the hypotenuse is  1: √2 so if the hypotenus = 10 the length of a leg is 10 / √2  

= 10 √2  / 2

= 5√2 .

7 0
3 years ago
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