Let X be the number of lightning strikes in a year at the top of particular mountain.
X follows Poisson distribution with mean μ = 3.8
We have to find here the probability that in randomly selected year the number of lightning strikes is 0
The Poisson probability is given by,
P(X=k) = 
Here we have X=0, mean =3.8
Hence probability that X=0 is given by
P(X=0) = 
P(X=0) = 
P(X=0) = 0.0224
The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224
Answer:
Yes.
Step-by-step explanation:
You are correct except to the nearest hundredth it is 795.54 cm^2.
Answer:
Step-by-step explanation:
This represents an arithmetic progression with the first term of a = 15 and common difference of d = 3.
<u>The tenth row is the 10th term:</u>
<u>The row 10 has:</u>
- a₁₀ = 15 + 9*3 = 15 + 27 = 42 seats
You pick only one letter, so the possible outcomes are:
A,C,O,M,D,T, I, N
if you need to probability of each outcome:
A: 2/13 (there are 2 As and a total of 13 letters)
C: 2/13
O: 3/13
ans so on.
use your calculator to change each fraction to a decimal if needed.
No, 2 of the 5x7 would actually take up. 10x14
