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3 years ago

Help me plsssssssssssssssssssssssssss

Mathematics

2 answers:

TiliK225 [7]3 years ago

8 0

Answer:

2 is F. 768 because all you have to do is mulltiply base times height oh and 7 is C

Step-by-step explanation:

Margarita [4]3 years ago

5 0

number 7 is as follows Answer: C18.9

Step-by-step explanation:

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides. so (5.65x2)+(3.8x2)=18.9 cm

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How do you find he Area please help

Artemon [7]

For a circle its Pier Squared

3 0

4 years ago

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below. See Attached Excel for Data. Assume t

motikmotik

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below.

16.5, 15.2, 15.4, 15.1, 15.3, 15.4, 16, 15.1

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans and fill in the blanks appropriately.

A 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is ( , ) ounces. (round to 3 decimal places)

Answer:

$99\% \: \text {confidence interval} = (14.886, \: 16.113)\\\\$

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

Step-by-step explanation:

Let us find out the mean amount of the 16-ounce beverage cans from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

$\bar{x} = 15.5$

Let us find out the standard deviation of the 16-ounce beverage cans from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$s = 0.4957$

The confidence interval is given by

$\text {confidence interval} = \bar{x} \pm MoE\\\\$

Where $\bar{x}$ is the sample mean and Margin of error is given by

$$ MoE = t_{\alpha/2} \cdot (\frac{s}{\sqrt{n} } ) $ \\\\$

Where n is the sample size, s is the sample standard deviation and is the t-score corresponding to a 99% confidence level.

The t-score corresponding to a 99% confidence level is

Significance level = α = 1 - 0.99 = 0.01/2 = 0.005

Degree of freedom = n - 1 = 8 - 1 = 7

From the t-table at α = 0.005 and DoF = 7

t-score = 3.4994

$MoE = t_{\alpha/2}\cdot (\frac{s}{\sqrt{n} } ) \\\\MoE = 3.4994 \cdot \frac{0.4957}{\sqrt{8} } \\\\MoE = 3.4994\cdot 0.1753\\\\MoE = 0.6134\\\\$

So the required 99% confidence interval is

$\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 15.5 \pm 0.6134\\\\\text {confidence interval} = 15.5 - 0.6134, \: 15.5 + 0.6134\\\\\text {confidence interval} = (14.886, \: 16.113)\\\\$

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

8 0

4 years ago

1. Joe created triangular shaped flag for his history project. The height of the flag was 16 cm and the

borishaifa [10]

The area of the flag that Joe created is 216 cm²

Step-by-step explanation:

Joe created triangular shaped flag for his history project

The height of the flag was 16 cm
The base of the flag was 27 cm

∵ The flag is shaped a triangle

∵ Area of a triangle = $\frac{1}{2}$ × base × height

∵ The base of the flag = 27 cm

∵ The height of the flag = 16 cm

- Substitute these values in the rule of the area above

∴ The area of the flag = $\frac{1}{2}$ × 27 × 16

∴ The area of the flag = 216 cm²

The area of the flag that Joe created is 216 cm²

Learn more:

You can learn more about area of a triangle in brainly.com/question/10677255

#LearnwithBrainly

3 0

4 years ago

Carbon-14 has a half-life of 5720 years and this is a first order reaction. If a piece of wood has converted 75% of the carbon-1

Doss [256]

The amount of the substance (At) at any time t is calculated through the equation,
At = (A0)(e^-kt)
where A0 is the initial amount and k is constant.

For the half-life,
ln (At / A0) = ln 0.5 = -k(5270 years)
The value of k is 1.3153x10^-4 / year.
Substituting this value to the same equation, where At = 0.25A0
ln 0.25 = -(1.3153 x 10^-4)(t)
The value of t from this equation is 10540 years. The closest value to this is letter A.

4 0

3 years ago

Read 2 more answers

Find the area of the following kite:

muminat

Answer:64

Step-by-step explanation:

2×2=4

4×2=8

8×8=64

7 0

3 years ago