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drek231 [11]
3 years ago
15

Steven purchases a bowl. THe diameter of the bowl is 14cm. What is the area of the bowl?

Mathematics
2 answers:
stellarik [79]3 years ago
8 0

Answer: 153.86cm

Step-by-step explanation:

A bowl represents a circle

Area of a circle is pir2

But here we are given the diameter as 14

Diameter = 2radii

14=2r

R=14/2

R=7

So radius of the bowl is 7cm

Back to the formula

Area of a circle is pir2

Pi=3.14

Substitute for each value

Area= 3.14×7^2

Area= 3.14×49

Area= 153.86cm

Area= ~154cm

belka [17]3 years ago
3 0

Answer 7?

Im not 100% sure. It is probably wrong

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sige and sa couple member a said weeks the a of days is will

8 0
2 years ago
gina painted 3/7 of a picture and George painted 2/7 of the picture. how much did they paint together
aliina [53]

Answer:

5/7 of the picture

Step-by-step explanation:

4 0
3 years ago
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
Find abc !!!!!!!! !!!!!
KonstantinChe [14]

Answer:

58 degreess

3x+11=4x-5

-3x      -3x

11=x-5

+5   +5

16=x

x=6

3(6)+11

18+11

29

29*2

58

Step-by-step explanation:

8 0
2 years ago
Solve this system of equations by any method.<br> 5x + y = -13<br> 4x + 3y= -17
irga5000 [103]
5x + y = -13.....multiply by -3
4x + 3y = -17
-----------------
-15x - 3y = 39 (result of multiplying by -3)
4x + 3y = -17
-----------------add
-11x = 22
x = -22/11
x = -2

5x + y = -13
5(-2) + y = -13
-10 + y = -13
y = -13 + 10
y = -3

solution (-2,-3)
5 0
3 years ago
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