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LUCKY_DIMON [66]
3 years ago
15

I meed help with this problem pls

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
7 0
Hey, I believe the answer to the question is A.
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Consider triangle ABC.
shusha [124]
Give me a second to get the answer and I’ll text you back
8 0
3 years ago
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Solve by factoring.<br><br> m^2+6m+5=0
alina1380 [7]

Answer:

<u>-1 and -5</u>

Step-by-step explanation:

m^2 + 6m + 5 = 0 is factored to: (m + 1)(m + 5) = 0.

The zero product property states that one of the represented parenthesis must equal zero to satisfy the right side of the equation.

(m + 1) = 0

(-1 + 1) = 0

This means that one of the values for m is -1.

(m + 5) = 0

(-5 + 5) = 0

This means that one of the values for m is -5.

<u>Moreover, the value of m by factoring is -1 and -5</u>

3 0
3 years ago
Which statement is true regarding the graphed functions?
Zigmanuir [339]

Answer:

the answer to your question is f(2)=0 and g(-2)=0

4 0
3 years ago
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Julio makes a scale drawing of the kitchen floor to determine how
tatuchka [14]

The scale drawing of Julio's kitchen would change the kitchen size

The actual area is 243 square feet

<h3>How to determine the actual area of Julio's kitchen?</h3>

The parameters are given as:

  • Length = 4.5 inches
  • Width = 3.375 inches

Start by converting the dimensions to feet using the scale ratio

  • Actual length = 4.5 inches/ (1 inch/ 4 feet) = 18 feet
  • Actual width = 3.375 inches/ (1 inch/ 4 feet) = 13.5 feet

The area is then calculated as:

Actual Area = Actual length * Actual Width

This gives

Actual Area =18 feet * 13.5 feet

Evaluate the product

Actual Area = 243 square feet

Hence, the actual area is 243 square feet

Read more about scale drawings at:

brainly.com/question/8975579

4 0
2 years ago
Please help if u see this
jek_recluse [69]
<h3>Answer: Choice D</h3>

(f \circ g)(x) = x+12

Domain = [-3, infinity)

==================================================

Work Shown:

f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\

In step 2, we replaced every x with g(x)

In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of (f \circ g)(x) as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

7 0
2 years ago
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