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Pepsi [2]
3 years ago
8

What are the values of (-2)4 and -24?

Mathematics
1 answer:
Lina20 [59]3 years ago
5 0

Follow the definition of exponents and the rules of multiplying positive and negative numbers.

(-2)^4 = (-2)(-2)(-2)(-2) = 4(-2)(-2) = -8(-2) = 16

-2^4 = -(2^4) = -[2(2)(2)(2)] = -[4(2)(2)] = -[8(2)] = -[16] = -16

Answer: The third choice, 16 and -16

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Kyle started biking at a constant rate of 15 mph. Half an hour later, Kim followed on the same path at a constant rate of 18 mph
lidiya [134]
The answer is...

It would take kim approximately* dont know if I spelled it correctly* 2 hours 30 minutes to catch up with kyle.
4 0
3 years ago
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1/4 + n = 2/3 *using the inverse operation*
Virty [35]

Answer:

Exact Form:

n = 5 /12

Decimal Form:

n= 0.41 6



hope this helps.

sorry if it doesn't

6 0
3 years ago
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Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

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3 years ago
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The unit rate in dollars per ounce would be $403.90.
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The correct answer is A, x-4
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