Ax^2+bx+c=0
find what 2 numbers multiply to get c and add to get b
x^2-4x-12
b=-4
c=-12
x times y=-12
x+y=-4
factor -12
-1, 12
-2,6
-3,4
add
-1+12=11
-2+6=4
-3+4=1
the one that works is -2 and 6 because they can be reversed to make -6 and 2 which multiploy to get -12 and add to get -4 so
split it up into
x^2-4x-12=(x-6)(x+2)=0
set each to zero
x-6=0
add 6
x=6
x+2=0
subtract 2
x=-2
x=6 or -2
Answer:
black screen
Step-by-step explanation:
Using the combination formula, it is found that the number of ways to choose the presenters is given by:
C. 462.
The order in which the presents are chosen is not important, hence the <em>combination formula</em> is used to solve this question.
<h3>What is the combination formula?</h3>
is the number of different combinations of x objects from a set of n elements, given by:
In this problem, 6 students are chosen from a set of 11, hence the number of ways is given by:
More can be learned about the combination formula at brainly.com/question/25821700
#SPJ1
Answer:
y = -
x + 7
Step-by-step explanation:
Ambos puntos (3, 5) y (6, 3) están en esta línea.
Answer:
The percentages are 267% and 400% respectively.
Step-by-step explanation:
To find the answers of these, you need to divide the second number by the first. This will give you the percentage.
2/3 ÷ 1/4 = 8/3 = 2.67 = 267%
You can do the same for the second one.
2/3 ÷ 1/6 = 12/3 = 4 = 400%
