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chubhunter [2.5K]
3 years ago
6

If you roll a fair six-sided die and a fair four-sided die, what is the probability that neither die shows a 1?

Mathematics
1 answer:
Masja [62]3 years ago
3 0
For the first die, 5 out of 6 are not 1. 
That is 5/6. 
For the second die, 3 out of 4 are not 1. 
That is 3/4.  
Multiply 5/6 by 3/4 to get the probability.
5/6 x 3/4 = 20/72 
Simplify once to get 10/36. 
Do it again to get 5/18. 
In decimal form it is 0.2777 and in percent form it is 27.77%. 
Hope this helps!

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Find the value of 7 + 32 (-5 + 1) ÷ 2.<br> A. 25<br> B. 32<br> C. -11
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  • as perhaps intended, C. -11

Step-by-step explanation:

The expression shown evaluates as ...

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If we assume your "32" is supposed to be 3², or 3^2, then the expression evaluates differently:

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When in doubt, you can have the Google calculator evaluate your expression. However, you do have to write it properly and with all the required parentheses.

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