Check the forward differences of the sequence.
If
, then let
be the sequence of first-order differences of
. That is, for n ≥ 1,

so that
.
Let
be the sequence of differences of
,

and we see that this is a constant sequence,
. In other words,
is an arithmetic sequence with common difference between terms of 2. That is,

and we can solve for
in terms of
:



and so on down to

We solve for
in the same way.

Then



and so on down to


Answer:
x=22
Step-by-step explanation:
Supplementary means that the two angles that are supplementary equal 180 degrees. 180-m<2=m<1
180-92=88 (m<2=92)
m<1=88
m<1=4x
4x=88
x=22
Answer:
-x + 2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
(x + 5) + (-4x - 2) + (2x - 1)
<u>Step 2: Simplify</u>
- Combine like terms (x): -x + 5 - 2 - 1
- Combine like terms (Z): -x + 2
Answer:
1. 1458
2. 500 or -500
Step-by-step explanation:
1. a4=54, a5=162
r = 162/54 = 3
a7 = a5 × r²
= 162 × 3² = 1458
2.a4=-4, a6=-100
r² = -100/-4 = 25
r = +/- 5
a7 = a6 × r
= -100 × +/- 5
= +/- 500
Answer:
the last one 1/6
Step-by-step explanation:
1/2 x 1/3 = 1/6