Answer:
3c=273
c=91
2c= 212
C= 106
c= 91+ 106= 197
so they will need 197 canoes total
Why:
So first you have to determine a set variable to represent the number of canoes, I chose C. Then you make an equation to represent the number of canoes 273 people will use if they group into 3's, from this I got 3c=273. Solve for C and get 91.
The remainder of the group which is 485-273= 212 will use canoes in groups of 2's. To represent this, 2c=212. Solve for C and get 106. Combine 106 and 91 to get the total number of canoes.
Vertex is directly in middle of directix and focus
distance from 8 to -8 is 16
16/2=8
so 8 below focus (since 8>-8) is the point (0,0
vertex is (0,0)
nice
it opens up because focus is above directix
also it goes up down so
4p(y-k)=(x-h)^2
(h,k) is veretx
we got that (h,k) is (0,0)
and p is distance from vertex to focus which is 8
so
4(8)(y-0)=(x-0)^2
32y=x^2
y=(1/32)x^2
Base=x+7 Height=x Area=60. 60=((x+7)(x))/2----->60=(x^2+7x)/2
120=x^2+7x X^2+7X-120=0. QUDRATIC FORMULA: -7+/- SQRT(49+480)/2
(-7+/-23)/2... 8 and -15. -15 ISNT the answer because you cant have a negative length. X=8 Base=8+7---->15 Height=8
Answer:
200 visitors went to screen 1.
125 visitors went to screen 2.
175 visitors went to screen 3.
Step-by-step explanation:
We will find number of visitors who went to screen 1 by finding 40% of 500 as we are told that 40% of 500 visitors went to screen 1.
Therefore, 200 visitors went to screen 1.
Now we will find number of visitors who went to screen 2. We are told that 25% of 500 visitors went to screen 2.
Therefore, 125 visitors went to screen 2.
Now we will find the number of visitors who went to screen 3 by subtracting combined number of visitors who went to screen 1 and screen 2 from total number of visitors.
Therefore, 175 visitors went to screen 3.
Answer: the graph farthest to the right is almost correct. If you substitute values for x in the function f(x)= -3√x , the output does not match the curve on the graphs shown.
If you have a choice that includes only a curve to the right of the y- axis, that would be better.
Step-by-step explanation: Square roots of Negative x-values will result in imaginary numbers. Otherwise the graph with the curve passing through coordinates (1,-3) (4,-6) and (9,-9) is a good choice.
(And ask your teacher about the square root of negative numbers on this graph.)
