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tankabanditka [31]
3 years ago
5

HELP ME PLEASEEE ILL GIVE BRAINLIEST ITS DUE TODAY

Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0
Dang… I wish I can help.
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A flea weighs 8 decigrams, and an ant weighs 3 milligrams. How much more does a flea weigh than an ant?
dusya [7]
In this question weight of a flea and an ant is given, but their units are different. So comparing and finding out the weight of flea and ant would be difficult. First thing that needs to be done is to bring the units of both the flea and the ant under same unit.
Weight of flea = 8 decigrams
Weight of ant = 3 milligrams.
Now let us convert the weight of the flea from decigrams to milligrams.
We already know that
1 decigram = 100 milligram
Then
8 decigrams = 100 * 8 milligrams
                     = 800 milligrams
Then
The weight by which the flea is greater than the ant = (800 - 3) milligrams
                                                                                   = 797 milligrams.
So the flea weighs 797 milligrams more than the ant.

5 0
4 years ago
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Find the value of x and y
IRISSAK [1]
A. x = 15 and y = 12
7 0
4 years ago
Explain prime factorization
kozerog [31]
Prime factorization is when a number can only be multiplied by 1 so 2 is a prime number because nothing times it self equals 2 or nothing but 1 ×2 is 2 prime factorization is just using prime numbers to break down bigger number like 50 5 and 10 and break down the 10 2 and 5
3 0
3 years ago
NEED HELP FAST PLEASE ANSWER IM DESPERATE!!!!!
balandron [24]
22 because you divide 44 into 4 because if one of the 3 sides is double the others you can divide by 4 and add the answer with itself and so the answer is 22
6 0
4 years ago
Factor the trinomial:<br> -3y^2 + 7y + 20
Sever21 [200]

Answer:

here you goes hope it helps you

Step-by-step explanation:

1

Common factor

−

3

2

+

7

+

2

0

-3y^{2}+7y+20

−3y2+7y+20

−

1

(

3

2

−

7

−

2

0

)

-1(3y^{2}-7y-20)

−1(3y2−7y−20)

2

Use the sum-product pattern

−

1

(

3

2

−

7

−

2

0

)

-1(3y^{2}{\color{#c92786}{-7y}}-20)

−1(3y2−7y−20)

−

1

(

3

2

+

5

−

1

2

−

2

0

)

-1(3y^{2}+{\color{#c92786}{5y}}{\color{#c92786}{-12y}}-20)

−1(3y2+5y−12y−20)

3

Common factor from the two pairs

−

1

(

3

2

+

5

−

1

2

−

2

0

)

-1(3y^{2}+5y-12y-20)

−1(3y2+5y−12y−20)

−

1

(

(

3

+

5

)

−

4

(

3

+

5

)

)

-1(y(3y+5)-4(3y+5))

−1(y(3y+5)−4(3y+5))

4

Rewrite in factored form

Solution

−

1

(

−

4

)

(

3

+

5

)

6 0
3 years ago
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