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klasskru [66]
2 years ago
5

How do you graph y = x + 2

Mathematics
1 answer:
Ghella [55]2 years ago
7 0

Answer:

Basically you first start with having a graph with positive and negative numbers on four sides. Then, you start with 2. You have to graph 2 on the  positive y section.

x = 1/1 so you go 1 up which means put another dot at 3 on the y section, then go 1 on the right. And thats it.

Please brainliest

Step-by-step explanation:

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TAKING TEST PLEASE HELP
kicyunya [14]

Answer:

A

Step-by-step explanation:

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8 0
3 years ago
Simplify the expression (6^4)^2
mote1985 [20]

Answer:

6^8.

This evaluates to 1,679,616.

Step-by-step explanation:

(6^4)^2

Using the law of logs (a^b)^c = a^bc:

(6^4)^2 = 6^(4*2)

= 6^8

This evaluates to 1,679,616.

7 0
3 years ago
What is the value of X? Enter answer as a decimal...
lozanna [386]

Answer:

37.89051724=x

Step-by-step explanation:

We can use similar triangles and proportions to solve.  Put the same side of the small triangle over the large triangle.

MA         MB

------- = ----------

MN         MP

80.5 -35         x

------------- = ----------

70.5               96.6 -x

Simplifying

45.5             x

------------- = ----------

70.5               96.6 -x

Using cross products

45.5 (96.6-x) = 70.5x

Distribute

4395.3 - 45.5 x = 70.5x

Add 45.5x to each side

4395.3 - 45.5 x+45.5x = 70.5x+45.5x

4395.3 = 116x

Divide each side by 116

4395.3/116 = 116x/116

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6 0
3 years ago
4/3x -3 ≤ -11<br><br> Please show how you got your answer!!
uranmaximum [27]

Answer:

-11+3=-8

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7 0
3 years ago
The terminal velocity of a person falling through air is about 100Km/hr. The acceleration due to gravity is 10ms−2. Use this inf
Aleonysh [2.5K]

The question here is how long does it take for a falling person to reach the 90% of this terminal velocity. The computation is:

The terminal velocity vt fulfills v'=0. Therefore vt=g/c, and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the differential equation shows that the time needed to reach velocity v is 

t= ln [g / (g-c*v)] / c. 

With v=.9 vt =.9 g/c,

t = ln [10] /c = 6.4 sec.

8 0
3 years ago
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