"Five times the difference of twice a number and three,
1 answer:
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Answer: About 12.083
Explanation:
In order to solve this you would use Pythagorean theorem.
You are given the length of the two legs (5 and 11)
So by plugging in 5 and 11 into A Squared plus B Squared = C Squared, you get that C^2= 146.
By finding the square root of both sides you get square root of 146, which is approximately 12.803
Explanation:
In order to solve this you would use Pythagorean theorem.
You are given the length of the two legs (5 and 11)
So by plugging in 5 and 11 into A Squared plus B Squared = C Squared, you get that C^2= 146.
By finding the square root of both sides you get square root of 146, which is approximately 12.803