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erastovalidia [21]
4 years ago
12

"Five times the difference of twice a number and three,

Mathematics
1 answer:
Gala2k [10]4 years ago
7 0

Answer:

4

Step-by-step explanation:

5(2x-3)-(x+8) = 13

10x-15-x-8 = 13

9x = 36

x = 4

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Answer:

The answer is 1

Step-by-step explanation:

i) \dfrac{(5\frac{4}{45} -4 \frac{1}{6})\div5\frac{8}{15}   }{(4\frac{2}{3} +0.75)\times3\frac{9}{13}}\times34\frac{2}{7} + \frac{0.3\div0.01}{70} + \frac{2}{7}

ii)\dfrac{(\frac{229}{45} -\frac{25}{6})\div\frac{83}{15}   }{(\frac{14}{3} +\frac{3}{4})\times\frac{48}{13}}\times\frac{240}{7} + \frac{30}{70} + \frac{2}{7}

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iii)(\dfrac{(\frac{458}{90} -\frac{375}{90})\times\frac{15}{83}   }{(\frac{56}{12} +\frac{9}{12})\times\frac{48}{13}}\times\frac{240}{7}) + \frac{30}{70} + \frac{2}{7}

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iv) (\dfrac{(\frac{83}{90})\times\frac{15}{83}   }{(\dfrac{65}{12} )\times\dfrac{48}{13}}\times\dfrac{240}{7}) + \dfrac{30}{70} + \dfrac{2}{7}

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v)(\dfrac{(\frac{1}{6})   }{(5\times4)}\times\dfrac{240}{7}) + \dfrac{30}{70} + \dfrac{20}{70}

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vi)(\dfrac{1}{(6\times5\times4)}\times\dfrac{240}{7}) + \dfrac{50}{70}

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vii)(\dfrac{1}{120}\times\dfrac{240}{7}) + \dfrac{50}{70}

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x)= \dfrac{70}{70} \hspace{0.2cm} = \hspace{0.2cm} 1

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