Answer:

Step-by-step explanation:

Hope this helps!
Answer:
If f(x) = 2x2 - 4x + 3 evaluate for f(3) and f(-4) 2. g(x) = V - 2x; find g(-27) and g(-1) ... {(-3,0), (+3, 3),(-3,2)} ... If f(x) = 5x+5, find and simplify f(4).
Answer:
A
Step-by-step explanation:
We have the expression 
We want to find the value when k is -3. So, substitute -3 for k and evaluate:

Multiply:

Subtract:

Add:

Therefore, our answer is A.
-4(8-3x)≥6x-8
Expand the left side.
-32+12x≥6x-8
Add 32 to both sides
12x≥6x+24
Subtract 6x.
6x≥24
Divide both sides by 6.
x≥4
Answer: x ≥ 4