D.) It is an "Element".
[ Element cannot be separated by any means ]
Hope this helps!
Answer:
The frequency heard by the motorist is 4313.2 Hz.
Explanation:
let f1 be the frequency emited by the police car and f2 be the frequency heard by the motorist, let v1 be the speed of the police car and v2 be the speed of the motorist and v = 343 m/s be the speed of sound.
because the police car is moving towards the motorist at a higher speed, then the motorist will hear a increasing frequency and according to Dopper effect, that frequency is given by:
f1 = [(v + v2/(v - v1))]×(f2)
= [( 343 + 30)/(343 - 36)]×(3550)
= 4313.2 Hz
Therefore, the frequency heard by the motorist is 4313.2 Hz.
Answer:
I would use a propeller like the first or second just from my experience. Just play around with the different ones and see which one works best for you.Don't make the propeller too thick or thin or else it may not work.
Explanation:
Have a great day! Good luck!
This question is asking the force on the rope. We can find this by using centripetal acceleration, then multiply by the ice skater's mass.
First we need to find the centripetal acceleration, which is a = v^2/r
We are given v and r, so we solve for a.
a = [(5.14m/s)^2]/(0.525m) = 50.323 m/s^2
Next multiply by the ice skater's mass (because F=ma) which is 44.6 kg
We then get F = (50.323m/s^2)(44.6kg) = 2244.407924N
Divide by 10^3 to get kN, we get:
2.244kN
Hope this helps!
B. North, was the correct answer
