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3 years ago

Which planet likely has flowing liquid matallic hydrogen as the source of its magnetic field

Physics

1 answer:

Sveta_85 [38]3 years ago

6 0

Answer:jupiter

Explanation:

Jupiter has flowing liquid metallic hydrogen as they source of it magnetic field

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You're carrying a 4.0-mm-long, 22 kg pole to a construction site when you decide to stop for a rest. You place one end of the po

Tju [1.3M]

Answer:

F = 118.14 N

Explanation:

For this exercise we will use the rotational equilibrium condition

∑ τ = I α = 0

Since the pole is in balance.

Let's fix a reference system located the point where the post rests on the fence, select the counterclockwise rotation as positive

-F (L -0.35) + W L / 2 = 0

F = W L / 2 (L-0.35)

L = 4.0 m

Let's calculate

F = 22 9.8 2 / 3.65

F = 118.14 N

6 0

3 years ago

The primary gas in a volcano is: carbon dioxide, sulfur dioxide, water vapor, nitrogen.

vaieri [72.5K]

Answer:

The primary components in volcanic gas are water vapor, carbon dioxide and sulfur (either sulfur dioxide or hydrogen sulfide). But you can also find nitrogen, argon, helium, neon, methane, carbon dioxide and hydrogen. Approximately 60% of total emissions released by volcanoes is water vapor, and carbon dioxide accounts for 10 to 40% of emissions.

Explanation:

7 0

3 years ago

Read 2 more answers

13. A lever does 5.0 J of work on a 0.10-kg ball bearing in a pinball machine. The ball's

shusha [124]

Answer:

The resulting speed of the ball is;

10 m/s

Explanation:

The given parameters are;

The amount of work done by the lever = 5.0 J

The mass of the ball on which the work is done, m = 0.10 kg

By the principle of conservation of energy, we have;

The work done by the lever = The kinetic energy. K.E., gained by the ball

The kinetic energy, K.E., is given by K.E. = 1/2·m·v²

Where, for the ball, we have;

m = The mass of the ball

v = The resulting speed of the ball

Therefore, by substituting the known values, we have;

The work done by the lever = 5.0 J = The kinetic energy. K.E., gained by the ball = 1/2 × m × v² = 1/2 × 0.10 kg × v²

∴ 5.0 J = 1/2 × 0.10 kg × v²

v² = 5.0 J/(1/2 × 0.10 kg) = 100 m²/s²

v = √(100 m²/s²) = 10 m/s

The resulting speed of the ball, v = 10 m/s.

6 0

3 years ago

a 3.00 kg object undergoes an acceleration given by a = (2.00 i + 5.00 j) m/s^2 find the resultant force acting on the object an

il63 [147K]

F = m.a

F = 3(2 I + 5 j)

F = 6i + 15j is resultant force

Magnitude force = √6+15 = √21

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3 years ago

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On a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 103 N/C. Compare the

Nina [5.8K]

Answer:

a) FE = 0.764FG

b) a = 2.30 m/s^2

Explanation:

a) To compare the gravitational and electric force over the particle you calculate the following ratio:

$\frac{F_E}{F_G}=\frac{qE}{mg}$ (1)

FE: electric force

FG: gravitational force

q: charge of the particle = 1.6*10^-19 C

g: gravitational acceleration = 9.8 m/s^2

E: electric field = 103N/C

m: mass of the particle = 2.2*10^-15 g = 2.2*10^-18 kg

You replace the values of all parameters in the equation (1):

$\frac{F_E}{F_G}=\frac{(1.6*10^{-19}C)(103N/C)}{(2.2*10^{-18}kg)(9.8m/s^2)}\\\\\frac{F_E}{F_G}=0.764$

Then, the gravitational force is 0.764 times the electric force on the particle

The acceleration of the particle is obtained by using the second Newton law:

$F_E-F_G=ma\\\\a=\frac{qE-mg}{m}$

you replace the values of all variables:

$a=\frac{(1.6*10^{-19}C)(103N/C)-(2.2*10^{-18}kg)(9.8m/s^2)}{2.2*10^{-18}kg}\\\\a=-2.30\frac{m}{s^2}$

hence, the acceleration of the particle is 2.30m/s^2, the minus sign means that the particle moves downward.

7 0

3 years ago