Answer:
N = 3032 turns
Explanation:
The magnetic field produced by a solenoid is described by
B = μ₀ n I
Where is the permittivity in a vacuum with a value of 4π 10⁻⁷ N /A², n is the turn density and I the current
Let's apply this equation to the problem, the turn density is the number of turns per unit length, in this case it is the same magnet length
L = 8 cm = 0.08 m
Let's calculate
B = μ₀ N/L I
N = B L / μ₀ I
N = 0.10 0.08 / (4π 10⁻⁷ 2.1)
N = 3,032 103 turns
Explanation:
The given data is as follows.
k = 130 N/m, = 17 cm = 0.17 m (as 1 m = 100 cm)
mass (m) = 2.8 kg
When the spring is compressed then energy stored in it is as follows.
Energy =
Now, spring energy gets converted into kinetic energy when the box is launched.
So, =
=
= 1.34
v = 1.15 m/sec
Now,
Frictional force =
=
= 4.116 N
Also, Kinetic energy = work done by friction
1.8515 =
d = 0.449 m
Thus, we can conclude that the box slides 0.449 m across the rough surface before stopping.
Is the velocity constant? Is there any friction?
3 meters per second
then after 40 seconds it must 3*40 = 120 meters
120 meters or 0.12 km if you will
For speed you can differentiate the equation, for acceleration you can again differentiate the equation .
at t=0 the particle is slowing down , when you get equation for velocity put t=0 then only -1 is left