Answer:
95 / 100 * 120 = 114 students
Thank you and please rate me as brainliest as it will help me to level up
C.Sphere is your answer it is bound to all it's points
Answer:
1/63
Step-by-step explanation:
There are a couple of ways to do this.
<h3>1) </h3>
Look for the GCF of the numerators when a common denominator is used.
GCF(3/7, 4/9) = GCF(27/63, 28/63) = (1/63)·GCF(27, 28)
GCF(3/7, 4/9) = 1/63
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<h3>2) </h3>
Use Euclid's algorithm. If the remainder from division of the larger by the smaller is zero, then the smaller is the GCF; otherwise, the remainder replaces the larger, and the algorithm repeats.
(4/9)/(3/7) = 1 remainder 1/63*
(3/7)/(1/63) = 27 remainder 0
The GCF is 1/63.
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* The quotient is 28/27 = 1 +1/27 = 1 +(1/27)(3/7)/(3/7) = 1 +(1/63)/(3/7) or 1 with a remainder of 1/63.
_____
<em>Additional comment</em>
3/7 = (1/63) × 27
4/9 = (1/63) × 28
Answer:
0.4444
Step-by-step explanation:
Use the following property to ease the calculation:
P(At least one)=1-P(None)
Total number of electrical components: 9
Number that does not function well :1
Number that functions well : 8
We have 
ways to to choose 4 good components from 8.
We have 
ways to choose 4 components from a total of 9.
If all function properly then none is bad, we 
way to do this.
P(At least one)=
P(At least one)=
P(At least one)=0.4444
The ratio of the volumes is equal to the scale factor cubed.
![\frac{V_1}{V_2}=k^3 \\ \\ \frac{320 \ cm^3}{1080 \ cm^3}=k^3 \\ \frac{8}{27}=k^3 \\ k=\sqrt[3]{\frac{8}{27}} \\ \boxed{k=\frac{2}{3}} \Leftarrow \hbox{answer B}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BV_2%7D%3Dk%5E3%20%5C%5C%20%5C%5C%0A%5Cfrac%7B320%20%5C%20cm%5E3%7D%7B1080%20%5C%20cm%5E3%7D%3Dk%5E3%20%5C%5C%0A%5Cfrac%7B8%7D%7B27%7D%3Dk%5E3%20%5C%5C%0Ak%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B8%7D%7B27%7D%7D%20%5C%5C%0A%5Cboxed%7Bk%3D%5Cfrac%7B2%7D%7B3%7D%7D%20%5CLeftarrow%20%5Chbox%7Banswer%20B%7D)
