Answer:
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To find where the second derivative of the function changes sign, from negative to positive, or vice-versa. So, we find the second derivative of the given function.
Answer:
Step-by-step explanation:
Depends on the tree.
If it's like a pine or spruce, then I would use maybe 2 inches lattitude. If it's really leafy with big leaves, perhaps a little more lattitude is needed, like maybe 1/2 a foot.
It also depends on the season. Unless the pine or spruce is covered with snow, I wouldn't change the latitude. If it is covered with snow, knock the snow off.
For something like a maple in winter, I'd reduce the latitude to 3 inches......
Answer:
133 ft
Step-by-step explanation:
Given in the question,
length of the rectangle = 31 ft
width of the rectangle= 20 ft
diameter of semicircle = 20 ft
radius of semicircle = 20/2 ft = 10 ft
Formula to use:
<h3>perimeter of rectangle + perimeter of semicircle</h3>
perimeter of rectangle = 2(l+w)
perimeter of semicircle = 1/2(2πr)
Plug values in the formula above
2(31 + 20) + 3.14(10)
133.4 ft
≈ 133 ft
