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3241004551 [841]
3 years ago
13

A paper company produces 675,000 tissues and 1,250 boxes in 5 days.

Mathematics
1 answer:
SashulF [63]3 years ago
4 0

The tissue production unit rate is _675000/5=135000_ tissues per day. <span>

<span>The box production unit rate is_1250/5=250_ boxes per day. </span>

<span>The paper company produces_135000/250=540_ times as many tissues per day as boxes per day. </span></span><span>

</span>

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Solve. <br> x^2-15x+50<br><br> (x-5)(x+10)<br> (x+5)(x+10)<br> (x-10)(x-5)<br> (x-10)(x+5)
fgiga [73]
C.)<span>(x-10)(x-5)
and that is grouping the factors </span>
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One should continue to monitor his or her goals and adjust his or her plan for achieving them when it is necessary A:true B:fals
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What is the value of E(-1) n (3n+2)?
RoseWind [281]
<h3>Answer:  C) 6</h3>

====================================================

Explanation:

The weird looking E symbol is the greek uppercase letter sigma. It refers to a sum.

It tells us to add up terms in the form (-1)^n*(3n+2) where n is an integer ranging from n = 1 to n = 4.

------------------

If n = 1, then we have

(-1)^n*(3n+2) = (-1)^1*(3*1+2) = -5

Let A = -5 as we'll use it later.

------------------

If n = 2, then

(-1)^n*(3n+2) = (-1)^2*(3*2+2) = 8

Let B = 8 since we'll use this later as well

------------------

If n = 3, then

(-1)^n*(3n+2) = (-1)^3*(3*3+2) = -11

Let C = -11

-------------------

If n = 4, then

(-1)^n*(3n+2) = (-1)^4*(3*4+2) = 14

Let D = 14.

--------------------

We'll add up the values of A,B,C,D to get the final answer

A+B+C+D = -5+8+(-11)+14 = 6

This means that

\displaystyle \sum_{n=1}^{4}(-1)^n(3n+2) = 6

6 0
3 years ago
Solve for y please help!!!!!
mrs_skeptik [129]

Answer:

148

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3p + 85 +2p -10 =180

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3p+85

3(21)+85=148

3 0
3 years ago
What is the decay factor of the exponential function<br> represented by the table?
bulgar [2K]

Given:

The table of values of an exponential function.

To find:

The decay factor of the exponential function.

Solution:

The general form of an exponential function is:

y=ab^x              ...(i)

Where, a is the initial value and 0 is the decay factor and b>1 is the growth factor.

The exponential function passes through the point (0,6). Substituting x=0,y=6 in (i), we get

6=ab^0

6=a(1)

6=a

The exponential function passes through the point (1,2). Substituting x=1,y=2,a=6 in (i), we get

2=6(b)^1

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Here, b=\dfrac{1}{3} lies between 0 and 1. Therefore, the decay factor of the given exponential function is \dfrac{1}{3}.

Hence, the correct option is A.

8 0
3 years ago
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