![\frac{b}{b-3} - \frac{5}{b} = \frac{3}{b-3} \\ \frac{ b^{2} -5(b-3)}{b(b-3)} =\frac{b}{b-3} \\ \frac{ b^{2} -5b+15}{b^2-3b} =\frac{b}{b-3} \\ (b-3)(b^{2} -5b+15)=b(b^2-3b) \\ b^3-8b^2+30b-45=b^3-3b^2 \\ 5b^2-30b+45=0 \\ b^2-6b+9=0 \\ (b -3)(b-3)=0 \\ b=3](https://tex.z-dn.net/?f=%20%5Cfrac%7Bb%7D%7Bb-3%7D%20-%20%5Cfrac%7B5%7D%7Bb%7D%20%3D%20%5Cfrac%7B3%7D%7Bb-3%7D%20%20%5C%5C%20%20%20%5Cfrac%7B%20b%5E%7B2%7D%20-5%28b-3%29%7D%7Bb%28b-3%29%7D%20%3D%5Cfrac%7Bb%7D%7Bb-3%7D%20%5C%5C%20%20%5Cfrac%7B%20b%5E%7B2%7D%20-5b%2B15%7D%7Bb%5E2-3b%7D%20%3D%5Cfrac%7Bb%7D%7Bb-3%7D%20%5C%5C%20%28b-3%29%28b%5E%7B2%7D%20-5b%2B15%29%3Db%28b%5E2-3b%29%20%5C%5C%20b%5E3-8b%5E2%2B30b-45%3Db%5E3-3b%5E2%20%5C%5C%205b%5E2-30b%2B45%3D0%20%5C%5C%20b%5E2-6b%2B9%3D0%20%5C%5C%20%28b%20-3%29%28b-3%29%3D0%20%5C%5C%20b%3D3)
To check: 3/3-3 - 5/3 = 3/0 - 5/3 which is not defined.
Therefore, b = 3 is an extraneous solution.
Show me the graphs. I have the answer.
The numbers of passengers that need to be booked to ensure the cruise line makes a profit, using a compound inequality is x ≥ 2,052 and x ≤ 2,462.
<h3>How to illustrate the inequality?</h3>
From the information given, we are told that the cruise ship needs to book at least 2,052 passengers to be profitable, but the most passengers the ship can accommodate is 2,462.
Learn x be the number of people that can be accommodated. Therefore, the model is x ≥ 2,052 and x ≤ 2,462.
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6(c+4)
In order to solve this problem you need to divide both coefficients by 6 and factor the rest out.
Answer:
Option d is correct.
Step-by-step explanation:
Discrete values are those which take an integer value not in fraction.
Option A is discrete because there will be certain number of students in class say 20 or 30
We can not have 20.5 students
Therefore, option a is correct.
Option B is not discrete because many people can have age say 65 and a half years and weight can be in decimals say 50.5 kgs.
Option C is correct because he is saving a proper integer number of money.
Therefore, option d is correct that is both A and C are correct.