Question

A cylindrical swimming pool has a diameter of 16 feet and a height of 3 feet. How many gallons of water can the pool contain? Around your answer to the nearest tenth. (1 ft3 = 7.5 gal)

Answer 1

Answer:

The pool can contain 4521.6 gallons of water.

Step-by-step explanation:

Given:

The diameter of the cylindrical swimming pool = 16 feet.

And the height of the cylindrical swimming pool = 3 feet.

(1 ft³ = 7.5 gallons)

Now, to find the gallons of water the pool can contain.

So, we find the radius first:

Radius (r) = $\frac{Diameter}{2}$ = $\frac{16}{2} =8\ feet.$

Height (h) = 3 feet.

Now, to get the volume of swimming pool which is cylindrical in shape by putting formula (using the value of π = 3.14):

$Volume=\pi r^2h$

$Volume=3.14\times 8^2\times 3$

$Volume=3.14\times 64\times 3$

$Volume=602.88\ feet^3.$

Thus, getting the volume of pool 602.88 feet³.

As, given 1 ft³ = 7.5 gallons.

Now, to get the gallons of water the pool can contain we multiply the volume of pool by 7.5:

$602.88\times 7.5$

$=4521.6\ gallons.$

Therefore, the pool can contain 4521.6 gallons of water.