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insens350 [35]
3 years ago
9

A cylindrical swimming pool has a diameter of 16 feet and a height of 3 feet. How many gallons of water can the pool contain? Ar

ound your answer to the nearest tenth. (1 ft3 = 7.5 gal)
Mathematics
1 answer:
kiruha [24]3 years ago
7 0

Answer:

The pool can contain <u>4521.6 gallons</u> of water.

Step-by-step explanation:

Given:

The diameter of the cylindrical swimming pool = 16 feet.

And the height of the cylindrical swimming pool = 3 feet.

(1 ft³ = 7.5 gallons)

Now, to find the gallons of water the pool can contain.

So, we find the radius first:

Radius (r) = \frac{Diameter}{2} = \frac{16}{2} =8\ feet.

Height (h) = 3 feet.

Now, to get the volume of swimming pool which is cylindrical in shape by putting formula (using the value of π = 3.14):

Volume=\pi r^2h

Volume=3.14\times 8^2\times 3

Volume=3.14\times 64\times 3

Volume=602.88\ feet^3.

<em>Thus, getting the volume of pool 602.88 feet³.</em>

<em>As, given 1 ft³ = 7.5 gallons</em>.

Now, to get the gallons of water the pool can contain we multiply the volume of pool by 7.5:

602.88\times 7.5

=4521.6\ gallons.

Therefore, the pool can contain <u>4521.6 gallons</u> of water.

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