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3 years ago

9

PLEASE HELP !!!! What is the slope of the line passing through the points (1, −5)(1, −5) and (4, 1)(4, 1)?

1 answer:

valentinak56 [21]3 years ago

4 0

Here's an example... So, in our last example... In the point ( -2, -1 ), x1 = -2 and y1 = -1 ... and, in the point ( 4, 3 ), x2 = 3 and y2 = 3 m = ( y2 - y1 ) / ( x2 - x1 ) = ( 3 - ( -1 ) ) / ( 4 - ( -2 ) ) = 4 / 6 = 2 / 3 But, notice something cool... The order of the points doesn't matter! Let's switch them and see what we get: In the point ( 4, 3 ), x1 = 4 and y1 = 3 ... and, in the point ( -2, -1 ), x2 = -2 and y2 = -1 m = ( y2 - y1 ) / ( x2 - x1 ) = ( -1 - 3 ) / ( -2 - 4 ) = -4 / -6 = 2 / 3 ... Same thing! Let's try our new formula with the second example in the last lesson: It was a line passing through ( -1, 4 ) and ( 2, -2 ) m = ( y2 - y1 ) / ( x2 - x1 ) = ( -2 - 4 ) / ( 2 - ( -1 ) ) = -6 / 3 = -2

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Suppose the average tread-life of a certain brand of tire is 42,000 miles and that this mileage follows the exponential probabil

Ahat [919]

Answer: The probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

Step-by-step explanation:

The cumulative distribution function for exponential distribution is :-

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As per given , we have

Average tread-life of a certain brand of tire : $\lambda=\text{42,000 miles }$

Now , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles will be :

$P(X\leq 65000)=1-e^{\frac{-65000}{42000}}\\\\=1-e^{-1.54761}\\\\=1-0.212755853158\\\\=0.787244146842\approx0.7872$

Hence , the probability that a randomly selected tire will have a tread-life of less than 65,000 miles is 0.7872 .

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4 years ago

LekaFEV [45]

Answer: $y-1=\dfrac32(x+3)$

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = $\dfrac{d-b}{c-a}$

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) = $\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}$

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope = is given by

$(y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)$

Required equation: $y-1=\dfrac32(x+3)$

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