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3 years ago

PLEASE HELP !!!! What is the slope of the line passing through the points (1, −5)(1, −5) and (4, 1)(4, 1)?

1 answer:

4 0

Here's an example... So, in our last example... In the point ( -2, -1 ), x1 = -2 and y1 = -1 ... and, in the point ( 4, 3 ), x2 = 3 and y2 = 3 m = ( y2 - y1 ) / ( x2 - x1 ) = ( 3 - ( -1 ) ) / ( 4 - ( -2 ) ) = 4 / 6 = 2 / 3 But, notice something cool... The order of the points doesn't matter! Let's switch them and see what we get: In the point ( 4, 3 ), x1 = 4 and y1 = 3 ... and, in the point ( -2, -1 ), x2 = -2 and y2 = -1 m = ( y2 - y1 ) / ( x2 - x1 ) = ( -1 - 3 ) / ( -2 - 4 ) = -4 / -6 = 2 / 3 ... Same thing! Let's try our new formula with the second example in the last lesson: It was a line passing through ( -1, 4 ) and ( 2, -2 ) m = ( y2 - y1 ) / ( x2 - x1 ) = ( -2 - 4 ) / ( 2 - ( -1 ) ) = -6 / 3 = -2

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Can someone help me with this ?

AysviL [449]

Use pythagora's theorem to solve it
c^2=a^2+b^2
x^2=(3/4)^2+1^2
x^2=25/16
x= 5/4 = 1 1/4 inch
therefore it is B

5 0

3 years ago

Read 2 more answers

Combine like terms to simplify the expression of -5.55-8.55c+4.35c

Rashid [163]

Answer:

-5.55-4.2c

Step-by-step explanation:

-5.55-8.55c+4.35c

-8.55c and 4.35c are like terms so you have to combine them.

-8.55c+4.35c=-4.2c

-5.55 is NOT a like term so it is on its own.

final answer -> -5.55-4.2c

*** don't forget -5.55 is negitive ***

hope this helped negative:)

4 0

3 years ago

The width of a rectangle is 10 centimeters and the length of the rectangle is 17 centimeters. Which measurement is closest to th

Leni [432]

The measurement which is closest to the length of the diagonal of this rectangle in centimeters is; 20 centimetres.

The diagonal of the rectangle is the line which divides the rectangle into 2 right angled triangles.

In essence, the diagonal of the rectangle is the hypothenus of either of the triangles and can be evaluated as follows;

By Pythagoras;

Diagonal, D² = 17² + 10²

D² = 289 + 100

D² = 389

D = √389

D = 19.72 centimeters.

D is approximately 20 centimetres.

Read more;

brainly.com/question/17033407

7 0

3 years ago

Find the largest side of △STU, given that m∠T=98°, m∠S=30°, and m∠U=52°.<br><br> geometry work

Sav [38]

<h3>Answer: SU</h3>

=======================================================

Explanation

Rule: The longest side of any triangle is always opposite the largest angle.

Angle T = 98 is the largest angle, so the longest side is SU since it is opposite angle T.

Refer to the diagram below.

4 0

3 years ago

Insert 3 rational numbers between

avanturin [10]

Answer:

$\frac{ \sqrt{20} }{20} \\ \sqrt{ \frac{1}{4} \times \frac{ \sqrt{20} }{20} } \\ \sqrt{ \frac{1}{5} \times \frac{ \sqrt{20} }{20} }$

Step-by-step explanation:

If you have two numbers x and y, their geometric mean is defined as

$\sqrt{xy}$

Let that number be m, and let x be the smallest of the two numbers.

You know for sure that

$x \leqslant m \leqslant y$

Since

$m \geqslant \sqrt{ {x}^{2} }$

And

$m \leqslant \sqrt{ {y}^{2} }$

With equality holding if and only if x=y.

So, we can use the geometric mean to generate numbers which are for sure between two desired values. For example:

$\frac{1}{4} < \sqrt{ \frac{1}{4} \times \frac{1}{5} } < \frac{1}{5}$

The middle term is of course irrational, since it's equal to

$\frac{1}{ \sqrt{20} } = \frac{ \sqrt{20} }{20}$

Now we can do the same thing with our newfound value which we know to be between 1/4 and 1/5:

$\frac{1}{4} < \sqrt{ \frac{1}{4} \times \frac{ \sqrt{20} }{20} } < \frac{1}{5}$

And

$\frac{1}{4} < \sqrt{ \frac{1}{5} \times \frac{ \sqrt{20} }{20} } < \frac{1}{5}$

8 0

3 years ago