Answer:
16.1
Step-by-step explanation:
Answer:
The answer w'll be obtained using formulas
cos(a+b) = cosacosb - sinasinb
cos(a-b) = cosacosb + sinasinb
Step-by-step explanation:
Using the trigonometric formula of addition and subtraction of cosine
cos(a+b) = cosacosb - sinasinb
cos(a-b) = cosacosb + sinasinb
w'll get the desired answer.
To be solve
L.H.S = R.H.S
sinasinb = (cos(a-b)-cos(a+b)/2
as we know that <u><em>cos(a+b) = cosacosb - sinasinb</em></u>
sinasinb = (cos(a-b) - (cosacosb -sinasinb))/2
as we know that <u><em>cos(a-b) = cosacosb + sinasinb</em></u>
sinasinb = ((cosacosb + sinasinb) - (cosacosb -sinasinb))/2
sinasinb = (cosacosb + sinasinb - cosacosb + sinasinb)/2
sinasinb = (2sinasinb)/2
sinasinb = sinasinb
hence L.H.S = R.H.S
The first is x-intercept without the -
I'm not too sure what you meant in the second part.
Answer:
No invariant point
Step-by-step explanation:
Hello!
When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:
1) Let's apply that translation to this polygon, a square. Check it below:
2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.
Examining the graph, we can see that no, there is not an invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.
m∠A + m∠B = 90, since the angles are complementary.
The question also tells us that m∠A = (2x + 10) and m∠B = (-x + 55)
So, all we have to do is input the angle's values into the first equation:
(2x+10) + (-x+55) = 90
Simplify:
x + 65 = 90
x = 25
Input the variable into the angles:
m∠A = 2(25) + 10 = 50 + 10 = <u>60°</u>
m∠B = -25 + 55 = <u>30°</u>