Square OABC is drawn on a centimetre grid. O is (0,0) A is (3,0) B is (3,3) C is (0,3) Write down how many invariant points ther
e are on the perimeter of the square when OABC is translated by the vector [1 3]
1 answer:
Answer:
No invariant point
Step-by-step explanation:
Hello!
When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:
1) Let's apply that translation to this polygon, a square. Check it below:
2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.
Examining the graph, we can see that no, there is not an invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.
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Answer:
<u>60</u> students are involved in either band or sports.
<u>95</u> students are not involved in either sports or band.
Step-by-step explanation:
Given:
In a school of 320 students, 85 students are in the band, 200 students are on sports teams, and 60 students participate in both activities.
Now, to find the students are involved in either sports or band. And students who are not involved in either sports or band.
<em>Total number of students</em> = 320.
Number of students in the band = 85.
Number of students in the sports team = 200.
Number of students participate in both activities = 60.
Thus, 60 students are involved in either band or sports.
So, the number of students in the band adding number of students in the sports team we get:
200 + 85 = 285.
Then, to subtract the number of students participate in both activities we get:
285 - 60 = 225.
<em>Thus, the remaining students are </em>= 225.
Now, to get the students who are not involved in either sports or band we subtract the total number of students from the remaining students:
Therefore, 60 students are not involved in either band or sports. 95 students are not involved in either sports or band.