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alex41 [277]
3 years ago
7

Square OABC is drawn on a centimetre grid. O is (0,0) A is (3,0) B is (3,3) C is (0,3) Write down how many invariant points ther

e are on the perimeter of the square when OABC is translated by the vector [1 3]

Mathematics
1 answer:
storchak [24]3 years ago
3 0

Answer:

No invariant point

Step-by-step explanation:

Hello!

When we translate a form, in this case a polygon We must observe the direction of the vector. Since our vector is:

\vec{v}=\left ( \begin{matrix}1\\ 3\end{matrix} \right )

1) Let's apply  that translation to this polygon, a square. Check it below:

2) The invariant points are the points that didn't change after the transformation, simply put the points that haven't changed.

Examining the graph, we can see that no, there is not an  invariant point, after the translation. There is no common point that belongs to OABC and O'A'B'C' simultaneously. All points moved.

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5 0
3 years ago
Give an example of a real number that is irrantional
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First let's see what does irrational mean.

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4 0
3 years ago
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olga_2 [115]
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5 0
4 years ago
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3 0
3 years ago
Read 2 more answers
By the congruent supplementary theorem, what can you conclude
valina [46]
Short Answer Only B is true.
Reasoning
A
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B 
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5 0
4 years ago
Read 2 more answers
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