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2 years ago

The lines given by the equations y=4x and y=0.25x are

Mathematics

1 answer:

d1i1m1o1n [39]2 years ago

6 0

They are not parallel because the slopes are different (slope of 4 and slope of 0.25)

Neither are they perpendicular. If they were then m1*m2 ( the product of their slopes) would be -1 ). The product of these slopes = 4*0.25 = 1)

So choice A is the correct one.

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Your take home pay is $1500 and you have 22% withheld in taxes. What is your gross pay?

wlad13 [49]

We have been given that the take home pay is $1500 and 22% is withheld as taxes.

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2 years ago

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Slope of the line 8x+6y=12

Harlamova29_29 [7]

The slope

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2 years ago

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PLEASE HELP ME!!!!!!!!!

vitfil [10]

$(x - 4) {}^{2} - 28 = 8 \\ (x - 4) {}^{2} = 8 + 28 \\ (x - 4) {}^{2} = 36$

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

$\sqrt{(x - 4) {}^{2} } = ± \sqrt{36} \\x - 4 = ±6 \\ x _{1}- 4 = 6 \: \: \: \: \: \: \: \: \: \: x _{2}- 4 = - 6 \\ x_{1} = 6 + 4 \: \: \: \: \: \: \: \: \: \: x_{2} = - 6 + 4 \\ x_{1} = 10 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x_{2} = - 2$

Well he started off correct to the point of completing the square.

$(x - 3) {}^{2} = 16 \\ x - 3 = ±4 \\ \: x_{1} - 3 = 4 \: \: \: \: \: \: \: \: \: \: \: \: x_{2} - 3 = - 4 \\ x_{1} = 7 \: \: \: \: \: \: \: \: \: \: x_{2} = - 1$

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5 months ago