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Minchanka [31]
3 years ago
8

I need help finding the RS, ST and RT​

Mathematics
2 answers:
inn [45]3 years ago
7 0

Answer:

RS = 38

ST = 22

RT = 60

Step-by-step explanation:

coldgirl [10]3 years ago
6 0

Answer:

so your awnser would be

Step-by-step explanation:

Daddy

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Mm<br> E<br> 9. Solve: 3(x+4) ≤36<br> x&gt; 8<br> x≤8<br> x≤12<br> X&gt;12
vampirchik [111]

Step-by-step explanation:

3(x+4) ≤ 36

3x + 12 ≤ 36

3x ≤ 24

x ≤ 8

4 0
2 years ago
Read 2 more answers
Give an example of a function fromNtoNthat isa)one-to-one but not onto.b)onto but not one-to-one.c)both onto and one-to-one (but
Marysya12 [62]

Answer:

Step-by-step explanation:

Let f be a function from N to N.

N_set of all natural numbers

i) one to one but not onto

consider the function

f(x) = x^2

When two numbers have same square we find that the numbers should be the same because they are positive.

So one to one but not onto because consider 3 it does not have square root in N.

ii) Onto but not one to one

Consider

f(x) = x, x odd\\f(x) = x/2, x even.

this is onto because every number has a preimage in N.

But not onto because consider 6 and 3, f(6) = 3 and f(3) =3

So not one to one

iii) both onto and one-to-one

f(x) = \\\\x-1,x odd

=x+1, x even

This is both one to one and onto since we consider only integers  

iv) Neither one to one nor onto

Consider the function

f(x) = 2

This is not onto because 3 cannot have a preimage in N, not one to one because f(1) = f(2) where 1 not equals 2

6 0
3 years ago
How many and what type of solutions does the equation have?
Oxana [17]
Here's how one would solve it:

17 + 3x2 = 6x
17 + 6 = 6x
23 = 6x
x = 23/6

There's only one solution.
8 0
3 years ago
jason says you can solve an inequality by replacing the inequality sign with an equal sign and putting it back in after solving
Dahasolnce [82]

Jason is incorrect, because inequality signs change when we multiply/divide by negative numbers, and we need to follow the signs to make sure we use the correct one.

<h3></h3><h3>Is Jason correct whit his claim?</h3>

Well, Jason says that you can solve an inequality by replacing the sign by an equal sign, solve the equation as you already have done a thousand times, and then put the inequality sign again.

Now, this is clearly incorrect, because inequalities have a really nice property. If you multiply or divide both sides of the inequality by a negative number, then the "direction" of the sign changes.

This means that if we have an inequality like:

-2x > 10

And we divide both sides by -2, we should get:

x < 10/-2

x < -5

Where the direction of the sign changed.

If you did what Jason said, the direction of that sign would not have changed, and thus, you would have got an incorrect solution for the inequality.

If you want to learn more about inequalities:

brainly.com/question/24372553

#SPJ1

4 0
1 year ago
If 2a + b = 13 and 3c-6a = 5, what is the value of b + c?
ElenaW [278]

Step-by-step explanation:

Solve the first eqn for b, b=13–2*a, and the 2nd for c, c=(6*a+5)/3. Then

b+c=13–2*a+(6*a+5)/3=13–2*a+2*a+5/3=44/3. We see that b+c has a definite value because the terms in a cancel.

7 0
3 years ago
Read 2 more answers
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