Solve the following system of equations.

2 answers:

8 0

7x + 4y = -8 (1)
-8x - 5y = 13 (2)

(2) + (1)
(-8x-5y)+(7x+4y) = (13)+(-8)
-8x-5y+7x+4y = 5
-x-y = 5 (3)

(3)x4
-4x-4y = 20 (4)

(4) + (1)
(-4x-4y)+(7x+4y) = (20)+(-8)
-4x-4y+7x+4y = 12
3x = 12
x = 4

Sub x=4 into (4)
-4x-4y = 20
-4(4)-4y = 20
-4y = 36
y = -9

Therefore x=4, y=-9.

kumpel [21]2 years ago

4 0

Answer:

x=4 and y=−9

Step-by-step explanation:

Problem:

Solve 7x+4y=−8;−8x−5y=13

Steps:

I will solve your system by substitution.

(You can also solve this system by elimination.)'

7x+4y=−8;−8x−5y=13

Step: Solve 7x+4y=−8 for x:

7x+4y+−4y=−8+−4y(Add -4y to both sides)

7x=−4y−8

7x/7 = -4y-8/7 (Divide both sides by 7)

x=-4/7y + -8/7

Step: Substitute -4/7y + -8/7 for x in −8x−5y=13:

−8x−5y=13

-8(-4/7y + -8/7) −5y=13

-3/7y + 64/7 =13(Simplify both sides of the equation)

-3/7y + 64/7 + -64/7 = 13 + -64/7 (Add (-64)/7 to both sides)

-3/7y = 27/7

-3/7y/-3/7 = 27/7/-3/7 (Divide both sides by (-3)/7)

y=−9

Step: Substitute −9 for y in x= -4/7y + -8/7:

x = -4/7y + -8/7

x = -4/7 (-9) + -8/7

x=4(Simplify both sides of the equation)

Answer:

x=4 and y=−9

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Answer:

7.2

Step-by-step explanation:

To reach point D from point C, you need to add 4 to the x-value of point C and take away 6 from the y-value. These numbers are the sides of the hypothetical triangle.

The Pythagorean Theorem states that $a^2+b^2=c^2$ . If we plug the side lengths in for a and b, we get $4^2 + 6^2 = c^2$ . This can be simplified to $16+36=c^2$ , or $52 = c^2$ . If we root both sides, we find that c is equal to $\sqrt{52}$ , which is slightly more than 7, at around 7.2.