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Vlad1618 [11]
3 years ago
9

When argon is placed in a container of neon, the argon spontaneously disperses throughout the neon because __________?

Chemistry
2 answers:
ella [17]3 years ago
7 0
The  argon    spontaneously  disperses   throughout   the  argon   because  dispersion  of  argon  atom   produces  an  increase  in  disorder.The  disorder  of  element  is  measured  by  use  of  entropy.According  to  the  second  law  of  thermodynamic  in  a  closed  system tend  to maximize entropy.
Anna35 [415]3 years ago
5 0
Answer is: the dispersion of argon atoms produces an increase in disorder.
Argon and neon are gases, so they have high kinetic energy and move through space (gases move more disorderly. Entropy (amount of disorder) of system increases, the higher the entropy the greater is disorder.
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How many moles are in 100.0g of gold
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HELPPP<br> What do you think caused this land formation ?
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Answer:

Erosion/Weathering

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6 0
3 years ago
Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu
pochemuha

Answer : The volume of CO_2 will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2

First we have to calculate the  mass of HCO_3^- in tablet.

\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g

Now we have to calculate the moles of HCO_3^-.

Molar mass of HCO_3^- = 1 + 12 + 3(16) = 61 g/mole

\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles

Now we have to calculate the moles of CO_2.

From the balanced chemical reaction, we conclude that

As, 1 mole of HCO_3^- react to give 1 mole of CO_2

So, 0.0202 mole of HCO_3^- react to give 0.0202 mole of CO_2

The moles of CO_2 = 0.0202 mole

Now we have to calculate the volume of CO_2 by using ideal gas equation.

PV=nRT

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = 37^oC=273+37=310K

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)

V=0.51411L=514.11ml

Therefore, the volume of CO_2 will be, 514.11 ml

6 0
3 years ago
Calculate the mass of 3 moles of clorine​
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4 0
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