To ensure that the 9-Fluorenone was totally dry, it had to be washed with methylene chloride. To make sure that methylene chloride is present in a pure solution, sodium sulfate binds to water and precipitates.
<h3>
What is the purpose of the sodium sulfate?</h3>
- Although it has numerous additional uses, sodium sulfate is primarily employed in the production of detergents and in the Kraft process of paper pulping.
- The decahydrate's natural mineral form, mirabilite, accounts for about half of the world's output, with the other half coming from chemical byproducts. Sodium sulfate was used as a drying, isolating, and anhydrous salt for the 9-fluorenone.
- To make sure that methylene chloride is present in a pure solution, sodium sulfate binds to water and precipitates.
- The sodium salt of sulfuric acid is known as sodium sulfate. Na2SO4 is the chemical formula for sodium sulfate. The mineral thenardite, which is also known as anhydrous sulfate, is described as a white, crystalline solid, whereas the decahydrate Na2SO4. 10H2O is also known as Glauber's salt or the mirabilis salt.
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Answer:
I think magniesum is combined with the sulfer which is why its at 3 omegas.
Hope this helps!
Explanation:
Answer:
131.5 kJ
Explanation:
Let's consider the following reaction.
CaCO₃(s) → CaO(s) + CO₂(g)
First, we will calculate the standard enthalpy of the reaction (ΔH°).
ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g)
) - 1 mol × ΔH°f(CaCO₃(s)
)
ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)
ΔH° = 179.2 kJ
Then, we calculate the standard entropy of the reaction (ΔS°).
ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g)
) - 1 mol × S°(CaCO₃(s)
)
ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)
ΔS° = 160.2 J/K = 0.1602 kJ/K
Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.
ΔG° = ΔH° - T × ΔS°
ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K
ΔG° = 131.5 kJ
When you are converting grams to moles, the operation that you will be doing is dividing by the molar mass to obtain the amount of moles of the given sample.
2.23 moles of propane react when 294 g of CO₂ is formed .
<h3>What is moles ?</h3>
Moles is a unit which is equal to the molar mass of an element.
A reaction is given
C₃H₈ +50₂ → 3CO₂ + 4H₂O
Grams of CO₂ formed = 294 gm
In moles = 294 /44 = 6.68 moles.
Let x be the moles of C₃H₈ is x
Mole ratio of CO₂ to C₃H₈ = 3 : 1
so
6.68 /x = 3/1
x = 6.68 /3 = 2.23 moles
Therefore 2.23 moles of propane react when 294 g of CO₂ is formed .
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