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den301095 [7]
2 years ago
9

What is a notifiable disease?

Chemistry
2 answers:
likoan [24]2 years ago
7 0

Answer:

D -- A disease that must be reported to the CDC.

Explanation:

Lerok [7]2 years ago
7 0

Answer:

A disease that must be reported to the CDC.

Explanation:

It has to reported to the goverment.

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What mass of H2 is needed to react with 8.75 g of O2 according to the following equation: O2(g) + H2(g) → H2O(g)?
alina1380 [7]

Mass of H₂ needed to react with O₂ : 1.092 g

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Reaction

O₂(g) + 2H₂(g) → 2H₂O(g)

mass of O₂ : 8.75 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{8.75}{32}=0.273

From the equation, mol ratio of O₂ : H₂ = 1 : 2, so mol H₂ :

\tt \dfrac{2}{1}\times 0.273=0.546

Mass H₂ (MW=2 g/mol) :

\tt 0.546\times 2=1.092~g

4 0
3 years ago
Read 2 more answers
What is the wavelength, in nm, of the light photon emitted by a hydrogen atom when an electron goes from n
xxMikexx [17]

Answer:

Hence, the wavelength of the photon associated is 1282 nm.

Explanation:

8 0
3 years ago
A sample of a substance that has a density of 0.824 g/mL has a mass of 0.451g. Calculate the volume of the sample.
Allushta [10]
Density can be calculated using the following rule:
density=mass/volume
therefore,
volume=mass/density

we have mass=0.451g and density=0.824g/ml
substituting in the above equation, we can calculate the volume as follows:
volume = 0.451/0.824 = 0.547 ml
8 0
4 years ago
What is the total enthalpy change for the reaction? Is the reaction exothermic or endothermic?
Nuetrik [128]

Answer: S8(s) + 8O2(g) → 8SO2(g) ΔH = -2368 kJ a.

8 0
3 years ago
What is the concentration of nitrate ion in a 425 mL solution containing 32.0 g of Mg(NO3)2 (M = 148.3)?
Butoxors [25]
Mg(NO3)2 ➡️ Mg2+ + 2 NO3-

(32.0g Mg(NO3)2) / (148.3g Mg(NO3)2/mol)* (2 mol NO3- / 1 mol Mg(NO3)2) / (0.425 L) = 1.02 mol/ L NO3-
6 0
3 years ago
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