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Phantasy [73]
2 years ago
10

What is atomic radius?​

Chemistry
2 answers:
vfiekz [6]2 years ago
7 0
The chemical element's atomic radius is measured by the size of its atoms, usually the medium or typical distance between the central nucleus and the surrounding electron shells. As the limit is not a well defined physical entity, different definitions of non-equivalent atomic radius exist.

Hope this helps!
Phoenix [80]2 years ago
3 0

Answer:

The atomic radius of a chemical element is the measure of the size of its atoms, usually the mean or typical distance from the centre of the nucleus to the boundary of surrounding shells of electrons

Hope it helps :)

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Calculate the molar mass of ammonium chloride
il63 [147K]

Answer:

53.491 g/mol

Explanation:

Create the chemical compound and find each individual element's molar mass. Lastly, add them up.

3 0
2 years ago
The law of definite proportions states that______.
Gwar [14]

Answer:

Law of definite proportions, statement that every chemical compound contains fixed and constant proportions (by mass) of its constituent elements.

5 0
2 years ago
Hello, everyone!
marusya05 [52]

Answer: 27.09 ppm and 0.003 %.

First, <u>for air pollutants, ppm refers to parts of steam or gas per million parts of contaminated air, which can be expressed as cm³ / m³. </u>Therefore, we must find the volume of CO that represents 35 mg of this gas at a temperature of -30 ° C and a pressure of 0.92 atm.

Note: we consider 35 mg since this is the acceptable hourly average concentration of CO per cubic meter m³ of contaminated air established in the "National Ambient Air Quality Objectives". The volume of these 35 mg of gas will change according to the atmospheric conditions in which they are.

So, according to the <em>law of ideal gases,</em>  

PV = nRT

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the constant gas (0.082057 atm L / mol K)

The moles of CO will be,

n = 35 mg x \frac{1 g}{1000 mg} x \frac{1 mol}{28.01 g}

→ n = 0.00125 mol

We clear V from the equation and substitute P = 0.92 atm and

T = -30 ° C + 273.15 K = 243.15 K

V =  \frac{0.00125 mol x 0.082057 \frac{atm L}{mol K}  x 243 K}{0.92 atm}

→ V = 0.0271 L

As 1000 cm³ = 1 L then,

V = 0.0271 L x \frac{1000 cm^{3} }{1 L} = 27.09 cm³

<u>Then the acceptable concentration </u><u>c</u><u> of CO in ppm is,</u>

c = 27 cm³ / m³ = 27 ppm

<u>To express this concentration in percent by volume </u>we must consider that 1 000 000 cm³ = 1 m³ to convert 27.09 cm³ in m³ and multiply the result by 100%:

c = 27.09 \frac{cm^{3} }{m^{3} } x \frac{1 m^{3} }{1 000 000 cm^{3} } x 100%

c = 0.003 %

So, <u>the acceptable concentration of CO if the temperature is -30 °C and pressure is 0.92 atm in ppm and as a percent by volume is </u>27.09 ppm and 0.003 %.

5 0
3 years ago
If the actual yielsd of a reaction is 50 g and the theoretical yield is 60 g. What is the percent yield.
balandron [24]
M₁=50 g
m₀=60 g

w=100m₁/m₀

w=100*50/60=83.3%
4 0
3 years ago
What functions of cells can be affected by a mutation?
Colt1911 [192]
It changes the rate of growth that cells usually undergo.
6 0
3 years ago
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