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Mamont248 [21]
2 years ago
15

Accounting procedures allow a business to evaluate their inventory costs based on two methods: LIFO (Last In First Out) or FIFO

(First In First Out). A manufacturer evaluated its finished goods inventory (in $000s) for five products with the LIFO and FIFO methods. To analyze the difference, they computed (FIFO − LIFO) for each product. We would like to determine if the LIFO method results in a lower cost of inventory than the FIFO method.
Product FIFO (F) LIFO (L)
1 225 221
2 119 100
3 100 113
4 212 200
5 248 245
What are the degrees of freedom
Mathematics
1 answer:
ivanzaharov [21]2 years ago
8 0

Answer: The FIFO method result in lower cost of inventory than the LIFO method.

Step-by-step explanation:

In the FIFO method old inventories are used to determine cost of goods sold (COGS), which result to less income because COGS is lesser, while it is greater in LIFO.

However, in LIFO, old and outdated inventories are valued lower than the present price. It not a good indicator of ending inventory value.

B. To calculate the degree of freedom of the inventory sample given: 1. 225221, 2. 119100, 3. 100113, 4. 212200, 5. 248245.

STEP 1. Find the mean or average of the samples.

Let x be the sample average, and N the sample size which is 5

x = 225221 + 119100 + 100113 + 212200 + 248245/5 = 180975.8

STEP 2. Degree of freedom Df is given as Df = N - 1

Remember, N is the sample size given as 5.

Df = 5 - 1 = 4.

CONCLUSION:

This shows that four numbers from the samples given have the freedom to vary as long as the average remains 180975.8.

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Answer:

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Step-by-step explanation:

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2 years ago
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
aliya0001 [1]

Answer:

f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...

We first compute the n-th derivative of f(x)=\ln(1+2x), note that

f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\

Now, if we compute the n-th derivative at 0 we get

f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!

and so the Maclaurin series for f(x)=ln(1+2x) is given by

f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2  \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}

3 0
2 years ago
A chameleon is looking for prey. Let positive numbers represent the elevation of prey above the chameleon and negative numbers r
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Answer:

B: The elevation of the chameleon

Step-by-step explanation:

The Fly is <em><u>above</u></em> the chameleon, so its elevation should be represented by a "positive number"(Example of positive number: 16)

Also,

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4 0
3 years ago
Someone pls help me with this and I’ll mark you as brainliest!!
MrRissso [65]

Answer:

2. I am pretty sure that it is right angles are congruent.

4. Angle O and R are congruent, never heard of their angles theorem but I think it might be related to CPCTC.

Step-by-step explanation:

Well a square is always used to represent a right angle so and both angle Q and N have squares and that should mean that they are both 90 degrees. Also while vertical angels are congruent, angles Q and N are not vertical from each other, Reflexive Property is if it is a side and not an angle I think.

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Answer:

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Step-by-step explanation:

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