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1 year ago

Which of the following is the equation for the graph shown?

Mathematics

1 answer:

Crank1 year ago

4 0

Answer:

x equals 0

Step-by-step explanation:

it is a vertical line on zero and this is 1st grade level math

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A local maximum of the function f(x) occurs for which x-value?

My name is Ann [436]

Answer:

-4

Step-by-step explanation:

the highest f(x) value on the table is at -4 on the x column

3 0

2 years ago

I’m like super confused can somebody help me please?

Nezavi [6.7K]

Equations are steeper when their slope's positive value is higher (ignore negatives when determining how steep a slope is). The slope is the value in front of x. If there isn't a value in front of x, then it is assumed to be 1.

4 0

2 years ago

For the function below, state the x-coordinate of the x-intercept that is located to the fight of the origin.

OLga [1]

Answer:

x = 3

Step-by-step explanation:

It should NOT be "fight of the origin", rather "right of the origin".

Now let's move on to solve the question...

The x-intercept is found by setting the function equal to 0. Thus:

0 = x^3 - 9x

Let's solve this using algebra:

$0=x^3-9x\\0=x(x^2-9)\\0=x(x-3)(x+3)$

Hence, x = -3 and x = 3

The coordinate that is to the right of the origin is the positive one, so x = 3 is the x-intercept we are looking for.

3 0

2 years ago

Read 2 more answers

Please help me with this geometry question. x and pr needed ao basically like this x=(answer), PR=(answer). Thank you

Dennis_Churaev [7]

Answer:

x = -1, PR = 38.

Step-by-step explanation:

As Q is the midpoint of PR

PQ = QR

6x + 25 = 16 - 3x

9x = -9

x = -1.

= 6x + 25 + 16 - 3x

= 6(-1) + 25 + 16 - 3(-1)

= -6 + 25 + 16 + 3

= 38.

7 0

1 year ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%E2%88%923x2%E2%88%9211x%2B7" id="TexFormula1" title="f(x) = −3x2&minus

bixtya [17]

Answer:

$x= \frac{ - 11 + \sqrt{205} }{6} \: \: \: \: \: or \: \: \: \: \\x = \frac{ - 11 - \sqrt{205} }{6}$

Step-by-step explanation:

$- 3x {}^{2} - 11x + 7 = 0 \\ 3x {}^{2} + 11x - 7 = 0$

here,

$a = 3 \\ b = 11 \\ c = - 7$

now,

$D = b {}^{2} - 4ac \\ = (11) {}^{2} - 4(3)( - 7) \\ = 121 + 84 \\ = 205 > 0 \\$

so,

$x = \frac{ - b + - \sqrt{b {}^{2} - 4ac} }{2a} \\ \\ = \frac{ - 11 + - \sqrt{205} }{2(3)} \\ = \frac{ - 11 + - \sqrt{205} }{6} \\ \\ = \frac{ - 11 + \sqrt{205} }{6} \: \: \: \: \: or \: \: \: \: = \frac{ - 11 - \sqrt{205} }{6}$

4 0

2 years ago