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Jet001 [13]
3 years ago
10

For what values of x is x2 + 2x = 24 true?

Mathematics
2 answers:
tekilochka [14]3 years ago
8 0
X² + 2x = 24 

Organizing:
x² + 2x - 24 = 0  
<<<< (<em>Quadratic </em><span><span><em>equation</em>)
</span>
</span><span>Delta:
</span>Δ = b²<span> - 4.a.c </span>
Δ = 2²<span> - 4 * 1 * -24 </span>
<span>Δ = 4 - 4 * 1 * -24 </span>
Δ = 100

<span>Bhaskara:
</span><span>x = (-b +- √Δ)/2*a
</span>
x' = (-2 + √100)/2*1   
x' = 8 / 2   
x' = 4   

x'' = (-2 - √100)/2*1
x'' = -12 / 2
x'' = -6

Result: x = 4 or<span> x = - 6 .
</span>
Good studies! :)
salantis [7]3 years ago
3 0
X²+2x=24
Subtract 24 to each side
x²+2x-24=24-24
x²+2x-24=0
Factor thus with
ax²+mx+nx+b
0=x²+6x-4x-24
0=x(x+6)-4(x+6)
0=(x-4)(x+6)
x-4=0
Add 4 to each side
x-4+4=0+4
x=4

x+6=0
Subtract 6 to each side
x+6-6=0-6
x=-6. As a result, x could equal to 4 and -6. Hope it help!
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Problem 1: Given the following probabilities P(Ac) = 0.45, P(B) = 0.34, and P(B|A) = 0.23. Find the following probabilities:
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P(A)=0.55

P(A and B)=P(A∩B)=0.1265

P(A or B)=P(A∪B)=0.7635

P(A|B)=0.3721

Step-by-step explanation:

P(A')=0.45

P(A)=1-0.45=0.55

P(B∩A)=?

P(B|A)=0.23

P(B|A)=(P(A∩B))/P(A)

0.23=(P(A∩B))/0.55

P(A∩B)=0.23×0.55=0.1265

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