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Jet001 [13]
3 years ago
10

For what values of x is x2 + 2x = 24 true?

Mathematics
2 answers:
tekilochka [14]3 years ago
8 0
X² + 2x = 24 

Organizing:
x² + 2x - 24 = 0  
<<<< (<em>Quadratic </em><span><span><em>equation</em>)
</span>
</span><span>Delta:
</span>Δ = b²<span> - 4.a.c </span>
Δ = 2²<span> - 4 * 1 * -24 </span>
<span>Δ = 4 - 4 * 1 * -24 </span>
Δ = 100

<span>Bhaskara:
</span><span>x = (-b +- √Δ)/2*a
</span>
x' = (-2 + √100)/2*1   
x' = 8 / 2   
x' = 4   

x'' = (-2 - √100)/2*1
x'' = -12 / 2
x'' = -6

Result: x = 4 or<span> x = - 6 .
</span>
Good studies! :)
salantis [7]3 years ago
3 0
X²+2x=24
Subtract 24 to each side
x²+2x-24=24-24
x²+2x-24=0
Factor thus with
ax²+mx+nx+b
0=x²+6x-4x-24
0=x(x+6)-4(x+6)
0=(x-4)(x+6)
x-4=0
Add 4 to each side
x-4+4=0+4
x=4

x+6=0
Subtract 6 to each side
x+6-6=0-6
x=-6. As a result, x could equal to 4 and -6. Hope it help!
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<h2> <u>Explanation</u><u>:</u></h2>

\bf \underline{★Given-} \\

\textsf{4x + 5y = 8};

\textsf{5x + 4y = 12}

\bf \underline{★To\: find-} \\

\textsf{the value of x and y in equation?}

\bf \underline{★Solution-} \\

\sf \leadsto 4x + 5y = 8 - - - (i)

\sf \leadsto 5x + 4y = 12 - - - (ii)

By first equation,

\sf \leadsto 4x + 5y = 8

\sf \leadsto 4x = 8 - 5y

\sf \leadsto x = \dfrac{8 - 5y}{4}

\textsf{Now, we can find the original value of Y.}\\

\sf \leadsto 5x + 4y = 12

\sf \leadsto 5 \bigg( \dfrac{8 - 5y}{4} \bigg) + 4y = 12

\sf \leadsto \dfrac{40 - 25y}{4} + 4y = 12

\sf \leadsto \dfrac{40 - 25y + 16y}{4} = 12

\sf \leadsto \dfrac{40 - 9y}{4} = 12

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\sf \leadsto -9y = 48 - 40

\sf \leadsto -9y =  8

\sf \leadsto y = \dfrac{ -8}{9}

\textsf{Now, we can find the original value of X.}\\

\sf \leadsto 4x + 5y = 8

\sf \leadsto  4x + 5 \bigg( \dfrac{ -8}{9} \bigg) = 8

\sf \leadsto 4x - \dfrac{40}{9} = 8

\sf \leadsto \dfrac{36x - 40}{9} = 8

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\sf \leadsto 36x = 72 + 40

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\sf \leadsto x = \dfrac{112}{36}

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Therefore, the values of x and y are -8/9 and 112/36 respectively.

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