How could you find out whether your credit card company or loan service

Solve the literal equation, C = 12h + 4. Justify each step

IceJOKER [234]

Answer:

slope=.083

c=4

h=-0.333..

Step-by-step explanation:

8 0

2 years ago

Write the equation of the line that passes through (3, 4) and (2, −1) in slope-intercept form. (2 points) a y = 3x − 7 b y = 3x

sashaice [31]

Answer: y = 5x − 11

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

The line passes through (3,4) and (2, -1),

y2 = - 1

y1 = 4

x2 = 2

x1 = 3

Slope,m = (- 1 - 4)/(2 - 3) = - 5/- 1 = 5

To determine the y intercept, we would substitute x = 3, y = 4 and m= 5 into

y = mx + c. It becomes

4 = 5 × 3 + c

4 = 15 + c

c = 4 - 15 = - 11

The equation becomes

y = 5x - 11

8 0

2 years ago

Which of the following statements has the same truth value as the statement "If it is Friday, then Bruce has beans for supper."?

Andrews [41]

The contrapositive of the statement p ⇒ q is not q ⇒ not p and both the statements are equivalent.

So, the contrapositive of the statement "If it is Friday, then Bruce has beans for supper" is "If Bruce does not have beans for supper, then, it is not Friday"

This is the last statement given and is the answer.

7 0

3 years ago

Read 2 more answers

What is the maximum height of of Anna's golf ball? The equation is y=x−0.04x2.

elena-s [515]

Given:

The height of a golf ball is represented by the equation:

$y=x-0.04x^2$

To find:

The maximum height of of Anna's golf ball.

Solution:

We have,

$y=x-0.04x^2$

Differentiate with respect to x.

$y'=1-0.04(2x)$

$y'=1-0.08x$

For critical values, $y'=0$ .

$1-0.08x=0$

$-0.08x=-1$

$x=\dfrac{-1}{-0.08}$

$x=12.5$

Differentiate y' with respect to x.

$y''=(0)-0.08(1)$

$y''=-0.08$

Since double derivative is negative, the function is maximum at $x=12.5$ .

Substitute $x=12.5$ in the given equation to get the maximum height.

$y=(12.5)-0.04(12.5)^2$

$y=12.5-0.04(156.25)$

$y=12.5-6.25$

$y=6.25$

Therefore, the maximum height of of Anna's golf ball is 6.25 units.

7 0

2 years ago

A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is

scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=360000$ represent the mean for the downtown restaurant

$\bar X_{2}=340000$ represent the mean for the freeway restaurant

$s_{1}=50000$ represent the sample standard deviation for downtown

$s_{2}=40000$ represent the sample standard deviation for the freeway

$n_{1}=36$ sample size for the downtown restaurant

$n_{2}=36$ sample size for the freeway restaurant

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis: $\mu_{1}\leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level $\alpha=0.05$ and $\alpha/2=0.025$ we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is $t_{1-\alpha/2}=1.66$

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874$

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

$p_v =P(t_{70}>1.874)=0.033$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0

2 years ago